如何测试通过xampp连接到mysqldb的php登录

你好，这是我在stackoverflow上的第一篇文章，我在php、mysql方面处于初级水平，并在连接到mysql数据库的php登录页面上工作，我确实尝试通过examplep测试该数据库，并得到以下错误消息

Warning: include(../storescripts/connect_to_mysql.php): failed to open stream: No such
file or directory in C:'xampp'htdocs'myonlinestore'storeadmin'admin_login.php 
on line 15
Warning: include(): Failed opening '../storescripts/connect_to_mysql.php' for
inclusion (include_path='.;C:'xampp'php'PEAR') in C:'xampp'htdocs'myonlinestore
'storeadmin'admin_login.php on line 15
Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in 
C:'xampp'htdocs'myonlinestore'storeadmin'admin_login.php on line 18
That information is incorrect, try again Click Here

我能够通过win7 64bit上的dreamwavercs6成功连接到mysql数据库，并为该数据库创建了一个用户，同时我还在创建的admin表中创建了一名具有完全权限的管理员。成功登录后，它会将您引导到名为index.php的后续页面，这是第二个仅供管理员选择任务的索引页面，位于同一目录的子文件夹中。主页index.php位于此处C:'xampp'htdocs'myonlinestore'index.php'

带有名为admin_login.php的脚本的文件显示在这里的下

<?php
session_start();
if (isset($_SESSION["manager"])){
header("location: index.php");
exit();
}
?>
<?php
if (isset($_POST["username"]) && isset($_POST["password"])){
$manager = preg_replace('#[^A-Za-z0-9]#i','',$_POST["username"]);
$password = preg_replace('#[^A-Za-z0-9]#i','',$_POST["password"]);
include "../storescripts/connect_to_mysql.php";
$sql = mysql_query("SELECT id FROM admin WHERE username='$manager' AND
password='$password' LIMIT 1");
$existCount = mysql_num_rows($sql);
if ($existCount == 1){
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
}
$_SESSION["id"] = $id;
$_SESSION["manager"] = $manager;
$_SESSION["password"] = $password;
header("location: index.php");
exit();
} else {
echo 'That information is incorrect, try again <ahref="index.php">Click Here</a>';
exit();
}
}
?>

此处下的脚本connect_to_mysql.php

 <?php 
$db_host = "localhost";
$db_username = "user"; 
$db_pass = "user"; 
$db_name = "myonlinestore_db";
mysql_connect("$db_host","$db_username","$db_pass") or die ("could not connect to
mysql");
mysql_select_db("$db_name") or die ("no database");             
?>

脚本index.php是登录页，从admin_login成功登录后，应将您重定向到此处下

<?php
session_start();
if(!isset($_SESSION["manager"])){
header("location: admin_login.php");
exit();
}
$managerID = preg_replace('#[^0-9]#i', '',$_SESSION["id"]);
$manager = preg_replace('#[^A-Za-z0-9]#i', '', $_SESSION["manager"]);
$password = preg_replace('#[^A-Za-z0-9]#i', '', $_SESSION["password"]);
include"../storescripts/connect_to_mysql.php";
$sql=mysql_query("SELECT*FROM admin WHERE id='$managerID' AND username='$manager' AND
password='$password' LIMIT 1"); // query the person
$existCount=mysql_num_rows($sql); // count the nums
if ($existCount==0){//evaluate the count
echo "Your login session data is not on record in the database";
exit();
}
?>

问题是，我无法通过firefox浏览器登录，并出现顶部提到的错误。我的firefox浏览器中的所有插件和扩展都处于禁用状态，并且选择了接受cookie，有人能帮助解决这个问题吗？

提前感谢