我的代码如下:
$xmlstring = '<Response>
<Auth>
<UserID>test</UserID>
<UserIP>123</UserIP>
<XmlVersion>Testing Version</XmlVersion>
</Auth>
<SearchAvailRequest>
<CountryCd>ID</CountryCd>
<CityCd>JOG</CityCd>
<CheckIn>2016-01-08</CheckIn>
<CheckOut>2016-01-09</CheckOut>
</SearchAvailRequest>
<SearchAvailResponse>
<Hotel>
<HotelNo>1</HotelNo>
<HotelCode>321</HotelCode>
<HotelName>Test 1 Hotel</HotelName>
<RmGrade>Deluxe</RmGrade>
<RmGradeCode>DLX</RmGradeCode>
</Hotel>
<Hotel>
<HotelNo>2</HotelNo>
<HotelCode>212</HotelCode>
<HotelName>Test 2 & 1 Hotel</HotelName>
<RmGrade>Deluxe</RmGrade>
<RmGradeCode>DLX</RmGradeCode>
</Hotel>
</SearchAvailResponse>
</Response>';
$xml = simplexml_load_string($xmlstring, "SimpleXMLElement", LIBXML_NOCDATA);
$json = json_encode($xml);
$array = json_decode($json,TRUE);
echo '<pre>';print_r($array);echo '</pre>';
?>
我想将XML转换为PHP数组。但我发现了一个错误:
Warning: simplexml_load_string(): Entity: line 24: parser error : xmlParseEntityRef: no name in C:'xampp'htdocs'ngetest'xml.php on line 268
Warning: simplexml_load_string(): <HotelName>Test 2 & 1 Hotel</HotelName> in C:'xampp'htdocs'ngetest'xml.php on line 268
Warning: simplexml_load_string(): ^ in C:'xampp'htdocs'ngetest'xml.php on line 268
这似乎是因为存在和象征(测试2和1酒店)。我还没有找到正确的解决方案来解决这个问题
关于如何解决这个问题,有什么建议吗?
非常感谢
试试这个:
$xmlparser = xml_parser_create();
xml_parse_into_struct($xmlparser,$xmlstring,$values);
xml_parser_free($xmlparser);
print_r($values);
希望这对你有帮助。