我用C编写了一个http客户端,并在我的服务器上创建了一个post方法,该方法正在运行一个php脚本,该脚本将接收客户端参数并向客户端发回一些响应。但是,成功套接字连接后,服务器将不返回任何内容。我的代码中缺少什么?
这是我的基于off-winsock2 的c客户端
/*
* Create a TCP socket
* @author Salim Said
* Jan 7 2016
*/
#include<stdio.h>
#include<winsock2.h>
#pragma comment(lib,"ws2_32.lib") //Winsock Library
int main(int argc , char *argv[])
{
WSADATA wsa;
SOCKET s;
struct sockaddr_in server;
char *message , server_reply[2000];
int recv_size;
printf("'nInitialising Winsock...");
if (WSAStartup(MAKEWORD(2,2),&wsa) != 0)
{
printf("Failed. Error Code : %d",WSAGetLastError());
return 1;
}
printf("Initialised.'n");
//Create a socket
if((s = socket(AF_INET , SOCK_STREAM , 0 )) == INVALID_SOCKET)
{
printf("Could not create socket : %d" , WSAGetLastError());
}
printf("Socket created.'n");
// server.sin_addr.s_addr = inet_addr("196.46.123.151");
server.sin_addr.s_addr = inet_addr("66.96.147.96");
server.sin_family = AF_INET;
server.sin_port = htons( 80 );
//Connect to remote server
if (connect(s , (struct sockaddr *)&server , sizeof(server)) < 0)
{
puts("connect error");
return 1;
}
puts("Connected");
//----------------------------------------------------------HTTP HEADER PLUS MESSAGE--------------------------------------//
message = "POST /echo.php HTTP/1.0'r'n Host: www.vocha.co.tz'r'n Content-type: application/x-www-form-urlencoded'r'n Content-Length: 16'r'n'r'n name=iAmWorking!";
if( send(s , message , strlen(message) , 0) < 0)
{
puts("Send failed");
return 1;
}
puts("Data Send'n");
//Receive a reply from the server
if((recv_size = recv(s , server_reply , 2000 , 0)) == SOCKET_ERROR)
{
puts("recv failed");
}
puts("Reply received'n");
//Add a NULL terminating character to make it a proper string before printing
server_reply[recv_size] = ''0';
//print the Server reply
puts(server_reply);
//show receive success message
puts("Data received successfully!");
//We are done receiving data! close the socket
closesocket(s);
WSACleanup();
return 0;
}
这是我的服务器端php脚本
<?php
// get name from post parameter and store it in variable $name
$name=$_POST['name'];
//echo back a greeting with the user's name
//this is what will appear in client's HTTP response
echo 'Hi ' . $name;
?>
这是服务器响应和调试消息的一部分。
Initialising Winsock...
Initialised.
Socket created.
Connected
Data Send
Reply received
<*****Missing response is supposed to appear here*****>
Data received successfully!
您的消息具有错误的HTTP语法格式,服务器在没有响应的情况下拒绝了它。
如果你拿这个:
message = "POST /echo.php HTTP/1.0'r'n Host: www.vocha.co.tz'r'n Content-type: application/x-www-form-urlencoded'r'n Content-Length: 16'r'n'r'n name=iAmWorking!";
意思是:
POST /echo.php HTTP/1.0[CR][LF]
[SP]Host: www.vocha.co.tz[CR][LF]
[SP]Content-type: application/x-www-form-urlencoded[CR][LF]
[SP]Content-Length: 16[CR][LF]
[CR][LF]
name=iAmWorking!
看到了吗?您在Header令牌之前添加了一个空格("''r''n"而不是"''r''n"),这是一个无效语法,服务器更喜欢静默地关闭tcp/ip连接,而不是花时间响应攻击者脚本(因为HTTP走私脚本可能会使用此选项)。