从php获取Json响应时遇到问题。我正在使用AngularJs来显示收到的Json数据。我是刚接触棱角分明的人，先尝试了一个简单的练习。请帮忙。提前谢谢。
index.html
<!DOCTYPE HTML>
<html ng-app="app">
<head>
<title>PHP MySQL API Consumed with AngularJS</title>
</head>
<body>
<div ng-controller="GetUsers">
<table border="1">
<thead><tr><th>ID</th><th>Name</th><th>City</th></tr></thead>
<tbody>
<tr ng-repeat="user in users"><td>{{user.user_id}}</td><td> {{user.first_name }}</td><td>{{user.user_city}}</td></tr>
</tbody>
</tfoot></tfoot>
</table>
</div>
<script>
var app = angular.module('app', []);
app.controller('GetUsers', function ($scope,$http){
$http.get('http://localhost/angmysql/api.php').success(function(data) {
$scope.users = data;
});
}
});
</script>
<script src="angular.js"></script>
<body>
</html>
api.php
<?php
$db_name = 'dbtuts';
$hostname = 'localhost';
$username = 'root';
$password = '';
$dbc = mysqli_connect('localhost','root','','dbtuts') or die('Error connecting to database');
$sql = mysqli_query($dbc,"SELECT * FROM users");
$emparray = array();
while($row =mysqli_fetch_assoc($sql))
{
$emparray[] = $row;
}
echo json_encode($emparray);
mysqli_close($dbc);
?>
$http传递给回调的参数是一个对象，其中响应体存储在.data字段中。
试试这个：
$http.get('http://localhost/angmysql/api.php').success(function(response) {
$scope.users = response.data;
});
来自AngularDocs
The response object has these properties:
data – {string|Object} – The response body transformed with the transform functions.
status – {number} – HTTP status code of the response.
headers – {function([headerName])} – Header getter function.
config – {Object} – The configuration object that was used to generate the request.
statusText – {string} – HTTP status text of the response.