我刚刚粘贴了我的示例输入&输出
样本输入：
Array
(
[0] => Array
(
[id] => 1
[msisdn] => 10
[sc] => 8155
)
[1] => Array
(
[id] => 2
[msisdn] => 20
[sc] => 22020
)
[2] => Array
(
[id] => 3
[msisdn] => 10
[sc] => 8155
)
[3] => Array
(
[id] => 4
[msisdn] => 10
[sc] => 8155
)
[4] => Array
(
[id] => 5
[msisdn] => 20
[sc] => 22020
)
[5] => Array
(
[id] => 6
[msisdn] => 30
[sc] => 22020
)
)
样本输出：
Array
(
[0] => Array
(
[id] => 1,3,4
[msisdn] => 10
[sc] => 8155
)
[1] => Array
(
[id] => 2,5
[msisdn] => 20
[sc] => 22020
)
[2] => Array
(
[id] => 6
[msisdn] => 30
[sc] => 8155
)
)
只需将特定值设为该键，然后在已推送/存在时进行连接：
$new_array = array();
foreach ($array as $value) {
if(!isset($new_array[$value['msisdn']])) {
// if not yet pushed, just initialize
$new_array[$value['msisdn']] = $value;
} else {
// if already inside, then just concatenate
$new_array[$value['msisdn']]['id'] .= ', ' . $value['id'];
}
}
$new_array = array_values($new_array);
echo '<pre>';
print_r($new_array);
样本输出
在代码板上直播：http://codepad.org/0fw9k2w9
您可以使用以下事实：在PHP中，数组是一个哈希映射。通过创建一个中间数组，您可以在O（n）时间内解决此问题。
$merged = array();
foreach($array as $v) {
$merged[$v['msisdn']][$v['sc']] [] = $v['id'];
}
$final = array();
foreach($merged as $msisdn=>$v) {
foreach($v as $sc=>$ids) {
$final [] = array('msisdn'=>$msisdn,'sc'=>$sc,'id'=>$ids);
}
}