下面的代码运行良好,它从文件夹中随机选择一个图像,并将其作为背景分配给生成的div。这很有效。如果我第二次使用这个代码,但使用它来简单地放置随机图像的img src,这也可以。但是,以与第一种相同的方式使用代码会破坏网站。我做错了什么?
<!-- BEGIN FEATURED 1 -->
<?php
try {
$conn = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbuser, $dbpass);
}
catch (PDOException $e) {
echo $e->getMessage();
echo 'Could not establish a connection to the database.';
}
$query = $conn->prepare('SELECT `articleid`,`title` FROM `news_articles` WHERE featured = 1 ORDER BY RAND() LIMIT 1');
$array = array(
'N'
);
$query->execute();
$results = $query->fetchAll(PDO::FETCH_COLUMN, 0);
foreach ($results as $row) {
}
$image = get_rand_img('images/featured_images/csgo/');
$title = $result['title'];
echo '<a href="index.php?viewarticle=1&articleid=' . $row . '">';?>
<div id="featured-image" style="height: 267px; width: 292px; background:url(/images/featured_images/csgo/<?php echo $image ?>)">
<?php
$result = $conn->prepare("SELECT `articleid`,`title`,`short_title` FROM `news_articles` WHERE articleid=$row");
$result->execute();
$rows = $result->fetch();
echo '<div class="featuredtitle1">';
echo $rows['short_title'];
echo '</div>';
echo '</div>';
echo '</a>';
?>
下面的代码破坏了网站。。(正如你所看到的,我现在已经把它评论掉了)。
<!-- BEGIN FEATURED 2 (Disabled) -->
<?php
/*
try {
$conn = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbuser, $dbpass);
}
catch (PDOException $e) {
echo $e->getMessage();
echo 'Could not establish a connection to the database.';
}
$query = $conn->prepare('SELECT `articleid` FROM `news_articles` WHERE featured = 1 ORDER BY RAND() LIMIT 1');
$array = array(
'N'
);
$query->execute();
$results = $query->fetchAll(PDO::FETCH_COLUMN, 0);
foreach ($results as $row) {
}
$image = get_rand_img('images/featured_images/dota/');
$title = $result['title'];
echo '<a href="index.php?viewarticle=1&articleid=' . $row . '">';?>
<div id="featured-image2" style="height: 267px; width: 292px; background:url(/images/featured_images/dota/<?php echo $image ?>)">
<?php
$result = $conn->prepare("SELECT `articleid`,`title`,`short_title` FROM `news_articles` WHERE articleid=$row");
$result->execute();
$rows = $result->fetch();
echo '<div class="featuredtitle2">';
echo $rows['short_title'];
echo '</div>';
echo '</div>';
echo '</a>';
*/
?>
我不明白为什么第一段代码很好,但再次复制会破坏它?
在编辑注释之前,我看到了一个关于将对象作为数组访问的致命错误。尝试从此更改您的代码:
$results = $query->fetchAll(PDO::FETCH_COLUMN, 0);
对此:
$results = $query->fetchAll(PDO::FETCH_ASSOC);