使用 php 抓取 HTML

我正在尝试从给定的文本中抓取以下文本

刮：

1. 答应我这个（呼吸之间，#4）

将

2. src 作为 http://d.gr-assets.com/books/1402555544l/22077246.jpg 的图像

3. 一段新的爱情将考验隔壁一个享有特权的男孩和那个纹身的蓝发女孩之间的激情界限，后者帮助他拥抱他狂野的一面......'''内特在校园里已经建立了相当花花公子的声誉。不是他不尊重或不信任女性;他不相信自己。内特家里的男人容易有虐待行为——这是内特一生都在逃避的肮脏秘密——所以内特不做关系。但是他无法控制自己在一个女孩身边......''杰西坚强，独立，在纹身店工作。内特忍不住靠近她，即使这完全是友谊。但没过多久，内特就承认，他想要和杰西在一起的不仅仅是友好。'''和杰西在一起，他可以做自己，探索他内心一直觉得的可怕的黑暗。即使内特开始以一种既震惊又让他恐惧的方式渴望她，杰西仍然想知道他的每一个部分。一起测试他们的界限需要一种信任，这种信任可能会使他们形影不离......或将它们撕开

.HTML：

<div class="leftAlignedImage bookBox">
<div class="coverWrapper" id="bookCover646987_22077246">
<a href="/book/show/22077246-promise-me-this"><img alt="Promise Me This (Between Breaths, #4)" class="bookImage" src="https://i.stack.imgur.com/NXMoh.jpg" title="" width="115" /></a>
</div>
<script type="text/javascript">
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            </div>

我是php和Xampp的新手，已经上网寻求帮助，但没有用。我已经从 Xampp 控制面板连接了 Apache，做了一个保存.php页面，其中我写了以下内容：

<?php
$html = file_get_contents('http://www.goodreads.com/genres/new_releases/art');
libxml_use_internal_errors( true);
$doc = new DOMDocument;
$doc->loadHTML( $html);
$xpath = new DOMXpath( $doc);
$node = $xpath->query( '//div[@name="coverWrapper"]')->item( 0);
echo $node->textContent;
?>

这给了我第 11 行
的错误错误：尝试在第 11 行的 C：''xampp''htdocs''xampp''ind''save.php中获取非对象的属性