需要以某种不同的方式在索引零处的数组


Need the array at index zero in some different manner

$i=0;
foreach($tagss as $tagdetails)
    {
        if($i==0)
 $tags_array[]["00"]=array("id"=>$i,"name"=>"all","type"=>"gift_finder","parent_id"=>null,"url"=>"all","readonly"=>"0","deleted"=>"0");

 $tags_array[][$tagdetails->id]=array("id"=>$tagdetails->id,"name"=>$tagdetails->title,"type"=>"gift_finder","parent_id"=>null,"url"=>$tagdetails->title,"readonly"=>"0","deleted"=>"0");

    $i++;
    }
echo json_encode($tags_array);

我上面的代码输出是:-

[{"00":{"id":0,"name":"all","type":"gift_finder","parent_id":null,"url":"all","readonly":"0","deleted":"0"}},{"1":{"id":"1","name":"Adventure","type":"gift_finder","parent_id":null,"url":"Adventure","readonly":"0","deleted":"0"}},{"2":{"id":"2","name":"cool","type":"gift_finder","parent_id":null,"url":"cool","readonly":"0","deleted":"0"}}] 

这是正确的,但我想要输出(只需要 0 而不是 00)所以我试了:-

   $i=0;
foreach($tagss as $tagdetails)
    {
        if($i==0)
 $tags_array[]["0"]=array("id"=>$i,"name"=>"all","type"=>"gift_finder","parent_id"=>null,"url"=>"all","readonly"=>"0","deleted"=>"0");

 $tags_array[][$tagdetails->id]=array("id"=>$tagdetails->id,"name"=>$tagdetails->title,"type"=>"gift_finder","parent_id"=>null,"url"=>$tagdetails->title,"readonly"=>"0","deleted"=>"0");

    $i++;
    }
echo json_encode($tags_array);

输出上述代码:-

[[{"id":0,"name":"all","type":"gift_finder","parent_id":null,"url":"all","readonly":"0","deleted":"0"}],{"1":{"id":"1","name":"Adventure","type":"gift_finder","parent_id":null,"url":"Adventure","readonly":"0","deleted":"0"}},{"2":{"id":"2","name":"cool","type":"gift_finder","parent_id":null,"url":"cool","readonly":"0","deleted":"0"}}] 

从逻辑上讲,它将第一个元素放在数组中并在第一个索引处处理下一个元素是正确的,但我需要单独的 0 索引

请提出任何建议提前谢谢.

总之我需要

[{"0":{"id":0,"name":"all","type":"gift_finder","parent_id":null,"url":"all","readonly":"0",
"deleted":"0"}},
{"1":"id":"1","name":"Adventure","type":"gift_finder","parent_id":null,"url":"Adventure","readonly":"0","deleted":"0"}},
{"2":"id":"2","name":"cool","type":"gift_finder","parent_id":null,"url":"cool","readonly":"0","deleted":"0"}
}] 

您只需要将选项传递给您的json_encode()调用。它是JSON_FORCE_OBJECT:

echo json_encode($tags_array, JSON_FORCE_OBJECT);

然后,您将能够为数字键生成一个对象(因此您根本不需要从 PHP 传递键)。请注意,从 PHP 5.3 开始可用