for($i=0; $i++; $i<4)
{
$nameselected = "a".$i;
echo "<select name="$nameselected" onChange='document.changet_form.submit()'>
<option value="apple">Volvo</option>
<option value="orange">Saab</option>
<option value="grape">Opel</option>
<option value="mango">Audi</option>
</select>";
}
获取 的名称:
if(($_REQUEST[$nameselected]) == "a0")
嗨,如何设置选择名称=[php变量名称]?我设置和获取的方式是否正确?谢谢:)
这应该有效:
for($i = 0; $i < 4; $i++) {
$nameselected = "a".$i;
echo '<select name="' . $nameselected . '" onChange="document.changet_form.submit()">
<option value="apple">Volvo</option>
<option value="orange">Saab</option>
<option value="grape">Opel</option>
<option value="mango">Audi</option>
</select>';
}
我想你在 for 循环中打错字了!