从 PHP Web 服务解析 JSON 对象时出错

我似乎从我的PHP Web服务中获得了一个不完整的JSON对象。我的PHP代码如下：

<?php
define('IEM_PATH', '../admin/com');
require_once('../admin/includes/config.php');
require_once('../admin/com/lib/IEM.class.php');
require_once ('../admin/com/lib/IEM/DBFACTORY.class.php');
require_once ('../admin/com/lib/IEM/baseAPI.class.php');
require_once ('../admin/com/lib/API/USERS.class.php');
require_once ('../admin/com/lib/IEM/baseRecord.class.php');
require_once ('../admin/com/lib/record/Users.class.php');
    function GetLists($userid = 0, $getUnconfirmedCount = false) {
        $userid = $_REQUEST['userID'];
        if (!$userid) {
        trigger_error('User object has no user id as parameter.', E_USER_NOTICE);
            return false;
        }

        if (!$userid) {
            $userid = $this->userid;
        }
        require_once('../admin/functions/api/lists.php');
        $listapi = new Lists_API();
        $returnA =  $listapi->GetListByUserID($userid, $getUnconfirmedCount);
        $returnResult1 = array();
            foreach ($returnA as $key => $value) { 
                //$lists[] = $key;
                $returnResult["contactList"][] = array("listID" => $returnA[$key]['listid'], "name" => $returnA[$key]['name']);
            }
       $returnResult["success"] = 1;
       echo json_encode($returnResult);
    }
    GetLists();

但是，当我尝试检索结果时，我的日志猫仅显示：

E/JSON Parser: Error parsing data org.json.JSONException: Value <br of type java.lang.String cannot be converted to JSONObject
W/System.err: org.json.JSONException: No value for success

通过执行日志记录，我的安卓返回我的 JSON 对象

D/Returned JSON: {"androidid":"1"}

从这些代码

// getting JSON response from PHP web service
JSONObject returnedJSONObj = listsJSONParser.makeHttpRequest(Constant.URL
                    + "RetrieveList.php", "GET", params);
Log.d("Returned JSON ", String.valueOf(returnedJSONObj));
success = returnedJSONObj.getInt("success");

我不明白为什么当我的 PHP 确实根据代码返回 JSON 数组以及成功值时没有成功值，但 android studio java 代码不会在 JSON 对象中检测到这些值。我在这里做错了什么？