我最近开始学习PHP，但联系表格有问题。
表单的问题在于它不会发送电子邮件，甚至在我发送之前也会在表单下方回显错误消息。有时我让它工作，然后它又坏了。
另外，我希望消息"消息已发送！"在发送时替换整个联系表单。如何在不链接到另一个页面的情况下做到这一点？
代码如下：
<form method="POST" action="index.php">
<input name="name" type="text" placeholder="Name">
<input name="email" type="email" required placeholder="Email">
<input name="subject" type="text" placeholder="Subject">
<textarea name="message" rows="15" required placeholder="Message"></textarea>
<input name="submit" type="submit" value="Send">
</form>
<?php
if(isset($_POST['submit']))
{
$name_field=$_POST['name'];
$email_field=$_POST['email'];
$subject_field=$_POST['subject'];
$message_field=$_POST['message'];
$to="example@outlook.com";
$from="example@outlook.com";
$subject="Contact Form Message";
$body="Name: $name_field'n Email: $email_field'n Subject: $subject_field'n Message:'n $message_field";
mail($to,$subject,$body,$from);
echo "<p>Message sent!</p>";
}
else
{
echo "<p>An error occured. Please try again.</p>";
}
?>
非常感谢您的任何帮助。另外，如果您知道如何使代码更好，更干净或更高效，请告诉！
你还没有说什么不起作用，但是如果表单已提交，则不显示表单，您希望将表单移动到php中，并且仅在表单尚未提交时才打印。
另外，为了进一步阅读以帮助您，这里有非常好的视频教程，这个教程专门用于制作联系表格:-Dhttp://thenewboston.org/watch.php?cat=11&number=100
如果表单尚未提交，您似乎也会回显错误消息，因此第一次加载时会出现错误。而且您的邮件命令看起来不正确。
<?php
//if the form hasn't been submitted yet, print the form.
if (!isset($_POST['submit'])){
print <<<END
<form method="POST" action="index.php">
<input name="name" type="text" placeholder="Name">
<input name="email" type="email" required placeholder="Email">
<input name="subject" type="text" placeholder="Subject">
<textarea name="message" rows="15" required placeholder="Message"></textarea>
<input name="submit" type="submit" value="Send">
</form>
END;
}
//if the form has been submitted.
if(isset($_POST['submit']))
{
$name_field=$_POST['name'];
$email_field=$_POST['email'];
$subject_field=$_POST['subject'];
$message_field=$_POST['message'];
$to="example@outlook.com";
$subject="Contact Form Message";
$body="Name: $name_field'n Email: $email_field'n Subject: $subject_field'n Message:'n $message_field";
$headers = "From: example@outlook.com";
if(!mail($to,$subject,$body,$headers)){
echo 'failed !!';
}
else{
echo "<p>Message sent!</p>";
}
}
试试这个，希望这对你有用：
<? if (!isset($_POST['submit']))
{?>
<form method="POST" action="test.php">
<input name="name" type="text" placeholder="Name">
<input name="email" type="email" required placeholder="Email">
<input name="password" type="password" required placeholder="Password">
<textarea name="message" rows="15" required placeholder="Message"></textarea>
<input name="submit" type="submit" value="Send">
</form>
<?
}
if(isset($_POST['submit']))
$name_field=$_POST['name'];
$email_field=$_POST['email'];
$subject_field=$_POST['subject'];
$message_field=$_POST['message'];
$to="example@outlook.com";
$from="example@outlook.com";
$subject="Contact Form Message";
$body="Name: $name_field'n Email: $email_field'n Subject: $subject_field'n Message:'n $message_field";
mail($to,$subject,$body,$from);
if($body)
echo "<p>Message sent!</p>";
if(!$body)
{
echo "<p>An error occured. Please try again.</p>";
}
}
?>