致命错误:在文件字段更新的非对象上调用成员函数 saveAs()


Fatal error: Call to a member function saveAs() on a non-object on FileField Update

我正在Yii上使用FileField。在创建时它工作正常,但我在更新时遇到了麻烦。

假设有人在filefield上保存了表单名称城市和图像,但忘记输入类型,因此更新表单,编辑类型并再次保存,这就是问题所在。在保存更新时,文件字段会删除之前上传的图像。我找到了一些代码,但现在不是保存和删除图像,而是向我发送此错误:

致命错误:在非对象上调用成员函数 saveAs()。

这是我的表格:

<?php 
Yii::app()->user->setFlash('success', '<strong>Well done!</strong> You successfully read this important alert message.');
$this->widget('bootstrap.widgets.TbAlert', array(
    'block'=>true, // display a larger alert block?
    'fade'=>true, // use transitions?
    'closeText'=>'×', // close link text - if set to false, no close link is displayed
    'alerts'=>array( // configurations per alert type
        'error'=>array('block'=>true, 'fade'=>true, 'closeText'=>'×'), // success, info, warning, error or danger
    ),
));
?>
<div class="form">
        <?php $form=$this->beginWidget('CActiveForm', array(
        'id'=>'reportes-form',
        'enableAjaxValidation'=>false,
        'htmlOptions' => array('enctype' => 'multipart/form-data'),
        )); ?>
        <?php echo $form->errorSummary($model); ?>
        <p class="help-block">Fields with <span class="required">*</span> are required.</p>
    <div class="row">
        <?php echo $form->labelEx($model, 'name'); ?>
        <?php echo $form->textField($model,'name'); ?>
        <?php echo $form->error($model, 'name'); ?>
    </div>
    <div class="row">
        <?php echo $form->labelEx($model, 'city'); ?>
        <?php echo $form->textField($model,'city'); ?>
        <?php echo $form->error($model, 'city'); ?>
    </div>
    <div class="row">
        <?php echo $form->labelEx($model,'id_type'); ?>
        <?php $datos = CHtml::listData(Types::model()->findAll(array('condition'=>'', 'order'=>'')), 'id', 'name');
            echo CHtml::activeDropDownList($model,'id_type',$datos,array('prompt'=>'Select', 'disabled'=> '')); 
        ?>
    </div>
    <div class="row" >
        <?php echo $form->labelEx($model, 'description'); ?>
        <?php echo $form->textArea($model,'description'); ?>
        <?php echo $form->error($model, 'description'); ?>
    </div>
    <div class="row">
        <?php echo $form->labelEx($model, 'image'); ?>
        <?php if ($model->image): ?>
            <div>Existing image: <?php echo CHtml::encode($model->image); ?></div>
            <div>
                <img src="<?php echo Yii::app()->request->baseUrl.'/images/uploads/'.$model->image?>" width="180" height="180" />
            </div>
        <?php endif; ?>
        <?php  echo $form->fileField($model, 'image'); ?>
        <?php echo $form->error($model, 'image'); ?>
    </div>
<div class="form-actions">
    <?php $this->widget('bootstrap.widgets.TbButton', array(
            'buttonType'=>'submit',
            'type'=>'primary',
            'label'=>$model->isNewRecord ? 'Create' : 'Save',
        )); ?>
</div>
<?php $this->endWidget(); ?>

这是我的控制器更新:

public function actionUpdate($id)
    {   
        $model=$this->loadModel($id);

        // Uncomment the following line if AJAX validation is needed
        // $this->performAjaxValidation($model);
        if(isset($_POST['Restaurants']))
        {
            $model->attributes=$_POST['Restaurants'];
            $oldFileName    = $_POST['Restaurants']['image'];
            $model->image= CUploadedFile::getInstanceByName('Restaurants[image]');
            $path = Yii::getPathOfAlias('webroot')."/images/uploads/";


            if($model->save()) {
                if($model->image == null){
                    $model->image->saveAs(Yii::getPathOfAlias('webroot')."/images/uploads/".$oldFileName);
                    $this->redirect(array('view','id'=>$model->id));
                }
                else
                {
                    $model->image->saveAs(Yii::getPathOfAlias('webroot')."/images/uploads/".$model->image);
                    chmod( $path.$model->image, 0777 );
                    $this->redirect(array('view','id'=>$model->id));

                }
            }
        }
        $this->render('update',array(
        'model'=>$model,
        ));
    }

$model->file进行var_dump会向我发送null,并且$oldFileName第一次上传图像的名称。所以我猜这应该可以节省旧名称$model->image而不会遇到麻烦。我错过了什么?

(在评论和编辑中回答。请参阅没有答案的问题,但问题在评论中得到解决(或在聊天中扩展) )

@Martin Komara写道:

我认为很明显,如果$model->image null,您就不能打电话给$model->image->saveAs(由于条件的原因,确实如此)。你想实现什么?是否要删除之前上传的文件?

查看此维基:http://www.yiiframework.com/wiki/349/how-to-upload-image-photo-and-path-entry-in-datebase-with-update-functionality/

您需要更新您的模型,即 $model->image = 'path to image'; $model->save();

OP写道:

我的更新控制器现在工作正常:

public function actionUpdate($id)
{
   $model=$this->loadModel($id);
    if(isset($_POST['Restaurants']))
    {
        $_POST['Restaurants']['image'] = $model->image;
        $model->attributes=$_POST['Restaurants'];
        $uploadedFile=CUploadedFile::getInstance($model,'image');
        if($model->save())
        {
            if(!empty($uploadedFile))  // check if uploaded file is set or not
            {
                $uploadedFile->saveAs(Yii::getPathOfAlias('webroot')."/images/uploads/".$model->image);
            }
            $this->redirect(array('view','id'=>$model->id));
        }
    }
    $this->render('update',array(
        'model'=>$model,
    ));
}