我正在尝试对两个关联数组的值求和。 这是第一个数组：
Array
(
[Jan 01, 2013] => Array
(
[COM] => 100
[RES] => 200
)
[Oct 28, 2014] => Array
(
[COM] => 300
[RES] => 400
)
)
这是第二个数组：
Array
(
[Jan 01, 2013] => Array
(
[COM] => 10
[RES] => 20
)
[Oct 28, 2014] => Array
(
[COM] => 30
[RES] => 40
)
)
我需要对这两个数组的值求和，以便产生以下结果：
Array
(
[Jan 01, 2013] => Array
(
[COM] => 110
[RES] => 220
)
[Oct 28, 2014] => Array
(
[COM] => 330
[RES] => 440
)
)
我发现本教程对关联数组的值求和，但它似乎不适用于我的多维数组。 有什么建议如何做到这一点吗？ 谢谢。
对第一个数组使用 foreach() 并检查第一个数组的键，无论它是否存在于第二个数组中。如果存在，则计算总和。例：
$arr1 = Array
(
"Jan 01, 2013" => Array
(
"COM" => 100,
"RES" => 200,
),
"Oct 28, 2014" => Array
(
"COM" => 300,
"RES" => 400,
)
);
$arr2 = Array
(
"Jan 01, 2013" => Array
(
"COM" => 10,
"RES" => 20,
),
"Oct 28, 2014" => Array
(
"COM" => 30,
"RES" => 40,
)
);
$arr3 = array();
foreach($arr1 as $key => $val):
if(array_key_exists($key, $arr2)):
$arr3[$key]["COM"] = $val["COM"] + $arr2[$key]["COM"];
$arr3[$key]["RES"] = $val["RES"] + $arr2[$key]["RES"];
endif;
endforeach;
print '<pre>';
print_r($arr3);
print '</pre>';
输出：
Array
(
[Jan 01, 2013] => Array
(
[COM] => 110
[RES] => 220
)
[Oct 28, 2014] => Array
(
[COM] => 330
[RES] => 440
)
)
试试这个：
<?php
$array_01 = array(
'a' => 1,
'b' => 2
);
$array_02 = array(
'a' => 0,
'b' => 1,
'c' => 2
);
/** first we should get the array keys union
* this is too long...,so you can make it better :D
* you can make this more readable
*/
$keyUnion = array_unique(array_merge(array_keys($array_01), array_keys($array_02)));
$res = array();
//sum
foreach ($keyUnion as $k => $v) {
$res[$v] = (isset($array_01[$v]) ? $array_01[$v] : 0) + (isset($array_02[$v]) ? $array_02[$v] : 0);
}
print_r($res);
?>
注意：代码只获取一维关联和
最直接/简单地说，迭代第二个数组的级别，并确定是应该将值附加到第一个数组中，还是合并求和到第一个数组中。
代码：（演示）
$arr1 = [
"Jan 01, 2013" => ["COM" => 100, "RES" => 200, "FOO" => 5],
"Oct 28, 2014" => ["COM" => 300, "RES" => 400]
];
$arr2 = [
"Jan 01, 2013" => ["COM" => 10, "RES" => 20],
"Oct 28, 2014" => ["COM" => 30, "RES" => 40]
];
foreach ($arr2 as $date => $set) {
foreach ($set as $key => $val) {
if (!isset($arr1[$date][$key])) { // val is unique to 1st array, set it
$arr1[$date][$key] = $val;
} else { // val already exists in 1st array, add 2nd val to 1st val
$arr1[$date][$key] += $val;
}
}
}
var_export($arr1);
由于您不知道传入数据的子数组键，并且您有关联键，因此您可以使用 array_merge_recursive() 以非常简单求和的方式合并两个数组。
根据关联值进行合并后，可以循环新的多维数组。 在迭代时，将子数组和子数组的值表示为"可通过引用修改"——这意味着 foreach 循环将处理实际数组而不是数组的副本。 实际上，这将使更改影响新阵列并通过$assoc_merged提供所需的结果。
代码：（演示）
$arr1 = [
"Jan 01, 2013" => ["COM" => 100, "RES" => 200, "FOO" => 5],
"Oct 28, 2014" => ["COM" => 300, "RES" => 400]
];
$arr2 = [
"Jan 01, 2013" => ["COM" => 10, "RES" => 20],
"Oct 28, 2014" => ["COM" => 30, "RES" => 40]
];
$assoc_merged =array_merge_recursive($arr1, $arr2);
// var_export($assoc_merged); // see what this makes
foreach ($assoc_merged as $date => &$set) {
foreach ($set as $key => &$val) {
$val = array_sum((array)$val);
// (array) forces a lone value to be an array containing one element; avoids generating Warnings
}
}
var_export($assoc_merged);
或其功能样式版本：（演示）
var_export(
array_map(
fn($set) => array_map(
fn($v) => array_sum((array) $v),
$set
),
array_merge_recursive($arr1, $arr2)
)
);
所有方法都产生相同的输出：
array (
'Jan 01, 2013' =>
array (
'COM' => 110,
'RES' => 220,
'FOO' => 5,
),
'Oct 28, 2014' =>
array (
'COM' => 330,
'RES' => 440,
),
)