CRUD with AngularJS and PHP


CRUD with AngularJS and PHP

我有以下代码:

var carregarUsuario = function () {
    $http.get("buscar.php").then(function (retorno){
        console.log(retorno.data);
        $scope.usuarios = retorno.data;
    });
};
carregarUsuario();

.PHP:

error_reporting(0);
$user = "root";
$password = "";
$db = "angulardb";
$host = "localhost";
$con = mysqli_connect("localhost", $user, $password, $db);
if (mysqli_connect_errno()){
  echo "Erro: " . mysqli_connect_error();
  }
$usuario = mysqli_query($con, "SELECT *  FROM users");
    header('Content-Type: application/json');
    $return = array();
    while ($dados = mysqli_fetch_assoc($usuario)) {
        array_push($return, $dados);
    }
    echo json_encode($return);

控制台或页面上未显示任何数据。我该如何解决此问题?

更新

当您在我的 PHP 代码中放置一个print_r时,就在我拥有的while之后(在.php页面中):

Array
(
    [0] => Array
        (
            [0] => 2
            [id] => 2
            [1] => João Silva
            [nome] => João Silva
            [2] => joao.silva@angular.com
            [email] => joao.silva@angular.com
            [3] => 123456
            [pass] => 123456
        )
    [1] => Array
        (
            [0] => 3
            [id] => 3
            [1] => Mario de Almeida
            [nome] => Mario de Almeida
            [2] => mario.almeida@angular.com
            [email] => mario.almeida@angular.com
            [3] => 123456
            [pass] => 123456
        )
)

仅使用控制台.log(retorno)我有:

Object {data: "", status: 200, config: Object, statusText: "OK"} 

控制台或页面上未显示任何数据。我该如何解决此问题?

伙计,u不能回显数组。使用 print_r(json_decode($array))

var carregarUsuario = function () {
    $http.get("buscar.php").then(function (retorno){
        console.log(retorno.data);
        $scope.usuarios = retorno.data;
    });
 return $scope.usuarios
};
carregarUsuario();

此外,您的函数不会返回任何内容。

问题解决了。显然,错误出在数据库的整理中。银行就像拉丁语,移动到utf8并正常运行.谢谢