目前我有2个不同的mysql查询：
查询 1
SELECT monthname( calendar.datefield ) AS date,
year(calendar.datefield) as year, calendar.datefield, COUNT(all_griefs_tbl.actioned_status ) AS total_griefs,
all_griefs_tbl.actioned_status, all_griefs_tbl.game
FROM all_griefs_tbl
RIGHT JOIN calendar
ON ( DATE(all_griefs_tbl.actioned_date ) = calendar.datefield )
AND all_griefs_tbl.actioned_status = 'accepted'
WHERE calendar.datefield
BETWEEN DATE_ADD(CURDATE(), INTERVAL -12 MONTH) AND CURDATE()
GROUP BY year( calendar.datefield ) DESC , month( calendar.datefield ) DESC
查询 2
SELECT monthname( calendar.datefield ) AS date,
year(calendar.datefield ) AS year, calendar.datefield,
COUNT(all_griefs_tbl.actioned_status ) AS total_submitted,
all_griefs_tbl.actioned_status, all_griefs_tbl.game
FROM all_griefs_tbl
RIGHT JOIN calendar
ON ( DATE( all_griefs_tbl.date ) = calendar.datefield )
WHERE calendar.datefield BETWEEN DATE_ADD( CURDATE( ) , INTERVAL -12 MONTH ) AND CURDATE( )
GROUP BY year( calendar.datefield ) DESC , month( calendar.datefield ) DESC
现在，它们之间的区别在于查询 1 我正在计算每月接受的悲伤数量，而在查询 2 中，我正在计算每月提交的记录数 - 计算不同的列
我想做的是 a） 将其放入单个查询或 b） 能够将结果合并到 1 个表中。
我希望输出如下：
Month Year Total Griefs Total Submitted
------------ ------------ ------------ ------------
April 2012 14 2
March 2012 0 8
February 2012 0 6
January 2012 0 13
December 2011 0 7
November 2011 0 10
October 2011 0 0
September 2011 0 0
August 2011 0 6
July 2011 0 3
June 2011 0 2
May 2011 0 0
April 2011 0 0
这可能吗，还是我完全吠错了树？
谢谢！
您可以在一个查询中执行此操作：
SELECT
monthname( calendar.datefield ) AS date,
year(calendar.datefield) as year,
calendar.datefield,
SUM(IF(all_griefs_tbl.actioned_status = 'accepted', 1, 0)) AS total_griefs,
COUNT(all_griefs_tbl.actioned_status ) AS total_submitted,
all_griefs_tbl.actioned_status,
all_griefs_tbl.game
FROM
all_griefs_tbl
RIGHT JOIN
calendar ON ( DATE(all_griefs_tbl.actioned_date ) = calendar.datefield )
WHERE
calendar.datefield BETWEEN DATE_ADD(CURDATE(), INTERVAL -12 MONTH) AND CURDATE()
GROUP BY year( calendar.datefield ) DESC ,
month( calendar.datefield ) DESC
编辑：这有点非正统，但它（很可能）会给你你想要的东西：
SELECT
month(date_add(curdate(), interval seq.mm months)),
year(date_add(curdate(), interval seq.mm months)),
(SELECT count(1)
FROM all_griefs_tbl
WHERE actioned_status = 'accepted'
AND month(action_date) = month(date_add(curdate(), interval seq.mm months))
AND year(action_date) = year(date_add(curdate(), interval seq.mm months))) as total_griefs
(SELECT count(1)
FROM all_griefs_tbl
AND month(date) = month(date_add(curdate(), interval seq.mm months))
AND year(date) = year(date_add(curdate(), interval seq.mm months))) as submitted_griefs
FROM
(SELECT -12 as mm UNION SELECT -11 as mmUNION SELECT -10 as mmUNION SELECT -9 as mm
UNION SELECT -8 as mm UNION SELECT -7 as mm UNION SELECT -6 as mm UNION SELECT -5 as mm
UNION SELECT -4 as mm UNION SELECT -3 as mm UNION SELECT -2 as mm UNION SELECT -1 as mm) seq
ORDER BY
mm
如果输出与 2 个查询相同，则可以将UNION与查询一起使用。
因此，将NULL AS total_griefs,和NULL AS total_submitted,添加到查询中，以便输出匹配
试试这个（我真的无法测试它）
SELECT monthname(calendar.datefield) AS date,
year(calendar.datefield) as year,
calendar.datefield,
SUM(CASE all_griefs_tbl.actioned_status
WHEN 'accepted' THEN 1
ELSE 0
END CASE) AS total_griefs,
COUNT(all_griefs_tbl.actioned_status) AS total_submitted,
all_griefs_tbl.actioned_status,
all_griefs_tbl.game
FROM all_griefs_tbl RIGHT JOIN calendar
ON DATE(all_griefs_tbl.actioned_date) = calendar.datefield
WHERE calendar.datefield
BETWEEN DATE_ADD(CURDATE(), INTERVAL -12 MONTH) AND CURDATE()
GROUP BY year(calendar.datefield) DESC,
month(calendar.datefield) DESC