>我花了超过 24 小时尝试在选择查询后运行更新或插入查询,但选择查询完成并在提交"displayID"时更新或插入从未完成的查询
代码##
if($_POST["displayid"]==TRUE) {
$sqlid = "SELECT * FROM doc1 WHERE idnum ='$pidnum' AND stats='$ok'";
$result = mysqli_query($conn, $sqlid);
if (mysqli_num_rows($result) > 0) {
$sqlup = "UPDATE doc1 SET m_phone='$pmphone', seen='$dataseen' WHERE idnum ='$pidnum'";
mysqli_query($conn, $sqlup);
$found=1;
}
else {
$found=0;
$sqlfail="INSERT INTO fail(fname,lname,tname,funame,idnum,m_phone,reg_date) VALUES('$pfname','$plname','$ptname','$pfuname','$pidnum','$pm_phone','$todaydate')";
$conn->query($sqlfail);
}
}
首先,您更新查询是错误的。要检查错误,请添加
error_reporting(E_ALL);
ini_set('display_errors', 1);
更新的代码
if ($_POST["displayid"] == TRUE) {
$sqlid = "SELECT * FROM doc1 WHERE idnum ='$pidnum' AND stats='$ok'";
$result = mysqli_query($conn, $sqlid);
if (mysqli_num_rows($result) > 0) {
$sqlup = "UPDATE doc1 SET m_phone='$pm_phone', seen='$dataseen' WHERE idnum ='$pidnum'";
mysqli_query($conn, $sqlup);
$found = 1;
} else {
$found = 0;
$sqlfail = "INSERT INTO fail(fname,lname,tname,funame,idnum,m_phone,reg_date)
VALUES ('$pfname','$plname','$ptname','$pfuname','$pidnum','$pm_phone','$todaydate')";
$conn->query($sqlfail);
}
}
$conn对象来自哪里? 试试这个。.
<?php
if($_POST["displayid"])
{
$sqlid = "SELECT * FROM doc1 WHERE idnum ='$pidnum' AND stats='$ok'";
$result = mysqli_query($conn, $sqlid);
if (mysqli_num_rows($result) > 0)
{
$sqlup= "UPDATE doc1 SET m_phone='$pm_phone' AND seen='$dataseen' WHERE idnum ='$pidnum'";
mysqli_query($conn, $sqlup);
$found=1;
}
else
{
$found=0;
$sqlfail="INSERT INTO fail(fname,lname,tname,funame,idnum,m_phone,reg_date)
VALUES('$pfname','$plname','$ptname','$pfuname','$pidnum','$pm_phone','$todaydate')";
mysqli_query($conn, $sqlfail);
}
}