我的代码根据用户连接速度检索视频。
我的代码上出现意外的语法错误。 在过去的几天里，我正在对此进行故障排除，并且对如何解决它已经没有想法了。
阿贾克斯代码
$.ajax({
method: "POST",
url: "viewvideo.php",
data: {speedMbps: speedMbps,
video_id: $('[name="video_id"').val()},
cache: false
}).done(function( html ) {
$( "#speed" ).val( html );
});
观看视频.php
if(isset($_POST['video_id']) && isset($_POST['speedMbps'] )){
$id = trim($_POST['video_id']);
$speed = $_POST['speedMbps'];
echo $id;
$result = mysqli_query($dbc , "SELECT `video_id`, `video_link` FROM `video480p` WHERE `video_id`='".$id."'");
$count = mysqli_num_rows($result);
if (($speed < 100) && ($count>0)) { //if user speed is less than 100 retrieve 480p quailtiy video
//does it exist?
//if($count>0){
//exists, so fetch it in an associative array
$video_480p = mysqli_fetch_assoc($result);
//this way you can use the column names to call out its values.
//If you want the link to the video to embed it;
echo $video_480p['video_link'];
}
else{
//does not exist
}
?>
<video id="video" width="640" height="480" controls autoplay>
<source src="<?php echo $video_480p['video_link']; ?>" type="video/mp4">
Your browser does not support the video tag.
</video>
<br />
<?php
$result2 = mysqli_query($dbc , "SELECT `video_id`, `video_link` FROM `viewvideo` WHERE `video_id`='".$video_id."'");
$count2 = mysqli_num_rows($result2);
// retrieve original video
else (($speed >= 100) && ($count2 >0)) {
//does it exist?
//if($count2>0){
//exists, so fetch it in an associative array
$video_arr = mysqli_fetch_assoc($result2);
//this way you can use the column names to call out its values.
//If you want the link to the video to embed it;
echo $video_arr['video_link'];
}
else{
//does not exist
}
}
?>
<video id="video" width="640" height="480" controls autoplay>
<source src="<?php echo $video_arr['video_link']; ?>" type="video/mp4">
Your browser does not support the video tag.
</video>
<br />
<?php
}
mysqli_close($dbc);
?>
您之前放置了一个没有if语句的 else 语句。
我认为您需要更改：
else (($speed >= 100) && ($count2 >0)) {
//does it exist?
//if($count2>0){
//exists, so fetch it in an associative array
$video_arr = mysqli_fetch_assoc($result2);
//this way you can use the column names to call out its values.
//If you want the link to the video to embed it;
echo $video_arr['video_link'];
}
else{
//does not exist
}
由：
if (($speed >= 100) && ($count2 >0)) {
//does it exist?
//if($count2>0){
//exists, so fetch it in an associative array
$video_arr = mysqli_fetch_assoc($result2);
//this way you can use the column names to call out its values.
//If you want the link to the video to embed it;
echo $video_arr['video_link'];
}
else{
//does not exist
}
您的else应该是if，并删除mysqli_close($dbc);之前的最后一}``
// retrieve original video
if (($speed >= 100) && ($count2 >0)) {
//does it exist?
//if($count2>0){
//exists, so fetch it in an associative array
$video_arr = mysqli_fetch_assoc($result2);
//this way you can use the column names to call out its values.
//If you want the link to the video to embed it;
echo $video_arr['video_link'];
}