JSON 数据值类型 - json data value type

json data value type

本文关键字：类型数据 JSON | 更新日期: 2023-09-27

我想将 json 数组值从字符串更改为来自 php 脚本的浮点值。这都是字符串类型。我希望它作为浮点类型。

[{"year":"2008","value":"4169.20"},
{"year":"2009","value":"4067.50"},
{"year":"2010","value":"4848.40"},
{"year":"2011","value":"5654.80"},
{"year":"2012","value":"6071.50"}]

但我希望它看起来像。可能吗？

[{"year":"2008","value":4169.20},
{"year":"2009","value":4067.50},
{"year":"2010","value":4848.40},
{"year":"2011","value":5654.80},
{"year":"2012","value":6071.50}]

最简单的

方法是在将数据编码到 JSON 之前将value转换为浮点数。

但是如果你只想在JS中工作：

var data = [ /* your data */ ];
data.forEach(function(item){
  item.value = +item.value;
});

输出：

[
  {"year":"2008","value":4169.2},
  {"year":"2009","value":4067.5},
  {"year":"2010","value":4848.4},
  {"year":"2011","value":5654.8},
  {"year":"2012","value":6071.5}
]

<?php
$data = '[{"year":"2008","value":"4169.20"},
{"year":"2009","value":"4067.50"},
{"year":"2010","value":"4848.40"},
{"year":"2011","value":"5654.80"},
{"year":"2012","value":"6071.50"}]';
$a = json_decode($data);
$b = array();
foreach ($a as $key => $v) {
 $c['year'] = $v->year;
 $c['value'] = (float) $v->value;
 $b[] = $c;
}
echo '<pre>';
print_r(json_encode($b));
echo '</pre>';
?>

演示

使用 javascript parseFloat（）函数：

例如

var b = parseFloat("10.00")

我只看到 JS 答案。我不知道你的意图是什么，但是如果你在 PHP 中有 jsong 字符串，你可以使用这样的东西：

$json = ' [
    {"year":"2008","value":"4169.20"},
    {"year":"2009","value":"4067.50"},
    {"year":"2010","value":"4848.40"},
    {"year":"2011","value":"5654.80"},
    {"year":"2012","value":"6071.50"}
]';
$jsonArray = json_decode($json);
foreach($jsonArray as $key => &$subArray)
{
    $subArray->value = (float) $subArray->value;
}
echo json_encode($jsonArray);

您有 2 个选项。

选项 1.

在应用程序的后端（php 代码），您可以将"值"转换为浮点数。例如：

$floatValue = (float) $strValue;

选项 2.

如果您无法编辑后端，请在每个"值"上使用 parseFloat。它将从响应中的字符串生成浮点数。

with preg_replace

$json = preg_replace('/"value":"('d+'.'d+)"/', '"value":$1',$json);