我正在使用symfony 3创建一个应用程序，该应用程序将用于为枪支靶场保留车道。我已经按照symfony 3文档来设置和配置登录和注册表单。我的注册表有效，但我的登录表单不起作用。无论如何，我只是得到"无效凭据"返回给我。
下面是我的安全 YML。
# To get started with security, check out the documentation:
# http://symfony.com/doc/current/book/security.html
security:
hide_user_not_found: false
encoders:
AppBundle'Entity'User:
algorithm: bcrypt
# http://symfony.com/doc/current/book/security.html#where-do-users-come-from-user-providers
providers:
our_db_provider:
entity:
class: AppBundle:User
firewalls:
# disables authentication for assets and the profiler, adapt it according to your needs
dev:
pattern: ^/(_(profiler|wdt)|css|images|js)/
security: false
main:
pattern: ^/
provider: our_db_provider
form_login:
login_path: /login
check_path: /login_check
csrf_token_generator: security.csrf.token_manager
username_parameter: _username
password_parameter: _password
logout: true
anonymous: true
access_control:
- { path: ^/profile, roles: ROLE_USER }
- { path: ^/reservation, roles: ROLE_USER }
这是我的登录控制器。
<?php
namespace AppBundle'Controller;
use Symfony'Bundle'FrameworkBundle'Controller'Controller;
use Sensio'Bundle'FrameworkExtraBundle'Configuration'Route;
use Symfony'Component'HttpFoundation'Request;
use AppBundle'Form'UserType;
use AppBundle'Entity'User;
class LoginController extends Controller
{
/**
* @Route("/login", name="login")
*/
public function loginAction(Request $request)
{
// loads security utilities
$authenticationUtils = $this->get('security.authentication_utils');
// get the login error if there is one
$error = $authenticationUtils->getLastAuthenticationError();
// last username entered by the user
$lastUsername = $authenticationUtils->getLastUsername();
// renders route
return $this->render('default/login.html.twig', [
'year' => date("Y"),
'error' => $error,
'last_user' => $lastUsername,
]);
}
/**
* @Route("/login_check", name="login_check")
*/
public function loginCheckAction()
{
}
}
这是我的存储库，因此您可以使用电子邮件或用户名登录
<?php
namespace AppBundle'Repository;
use Symfony'Bridge'Doctrine'Security'User'UserLoaderInterface; use Symfony'Component'Security'Core'User'UserInterface; use Symfony'Component'Security'Core'Exception'UsernameNotFoundException; use Doctrine'ORM'EntityRepository;
class UserRepository extends EntityRepository implements UserLoaderInterface {
public function loadUserByUsername($username)
{
$user = $this->createQueryBuilder('u')
->where('u.username = :username OR u.email = :email')
->setParameter('username', $username)
->setParameter('email', $username)
->getQuery()
->getOneOrNullResult();
if (null === $user) {
$message = sprintf(
'Unable to find an active admin AppBundle:User object identified by "%s".',
$username
);
throw new UsernameNotFoundException($message);
}
return $user;
} }
这是我的用户实体
<?php
namespace AppBundle'Entity;
use Doctrine'ORM'Mapping as ORM;
use Symfony'Component'Validator'Constraints as Assert;
use Symfony'Bridge'Doctrine'Validator'Constraints'UniqueEntity;
use Symfony'Component'Security'Core'User'UserInterface;
/**
* User
*
* @ORM'Table(name="user")
* @ORM'Entity(repositoryClass="AppBundle'Repository'UserRepository")
*/
class User implements UserInterface, 'Serializable
{
/**
* @var int
*
* @ORM'Column(name="id", type="integer")
* @ORM'Id
* @ORM'GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @ORM'Column(type="string", length=25, unique=true)
*/
private $username;
/**
* @Assert'NotBlank()
* @Assert'Length(max = 4096)
*/
public $plainPassword;
/**
* @ORM'Column(type="string", length=64)
*/
private $password;
/**
* @ORM'Column(type="string", length=60, unique=true)
*/
private $email;
/**
* @ORM'Column(name="is_active", type="boolean")
*/
private $isActive;
public function __construct()
{
$this->isActive = true;
}
public function getUsername()
{
return $this->username;
}
public function getSalt()
{
return null;
}
public function getPassword()
{
return $this->password;
}
public function getPlainPassword()
{
return $this->password;
}
public function getRoles()
{
return array('ROLE_USER');
}
public function eraseCredentials()
{
}
/** @see 'Serializable::serialize() */
public function serialize()
{
return serialize(array(
$this->id,
$this->username,
$this->password,
));
}
/** @see 'Serializable::unserialize() */
public function unserialize($serialized)
{
list (
$this->id,
$this->username,
$this->password,
) = unserialize($serialized);
}
/**
* Get id
*
* @return integer
*/
public function getId()
{
return $this->id;
}
/**
* Set username
*
* @param string $username
*
* @return User
*/
public function setUsername($username)
{
$this->username = $username;
return $this;
}
/**
* Set password
*
* @param string $password
*
* @return User
*/
public function setPassword($password)
{
$this->password = $password;
return $this;
}
/**
* Set email
*
* @param string $email
*
* @return User
*/
public function setEmail($email)
{
$this->email = $email;
return $this;
}
/**
* Get email
*
* @return string
*/
public function getEmail()
{
return $this->email;
}
/**
* Set isActive
*
* @param boolean $isActive
*
* @return User
*/
public function setIsActive($isActive)
{
$this->isActive = $isActive;
return $this;
}
/**
* Get isActive
*
* @return boolean
*/
public function getIsActive()
{
return $this->isActive;
}
}
不知道发生了什么，但我真的很感激一些帮助。
谢谢罗伯特
快速概览说您忘记将属性字段添加到提供程序配置中。也许，问题不在于此，但无论如何：
providers:
our_db_provider:
entity:
class: AppBundle:User
property: username
我还建议在实体的设置器中对密码进行编码：
public function setPassword($password) {
if ($password)
$this->Password = password_hash($password, PASSWORD_DEFAULT);
return $this;
}
并确保数据库中的密码确实已编码。如果您放置了未编码的密码，您将无法使用它。只需转到phpMyAdmin或任何其他工具并检查即可。可能是，您在用户创建过程中遇到了错误。