我正在学习PHP,并编写了一个简单的翻译器。
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Translator</title>
</head>
<body>
<form method="post" action="">
<input type="string" name="word">
<input type="submit">
</form>
<?php
if (isset($_POST["word"])) {
$word = $_POST["word"];
echo $word . " -> ";
function translate($word){
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
foreach ($dict as $en => $th) {
if ($word == $en) {
echo $th;
break;
}
}
}
translate($word);
} else {
echo "enter a word";
}
?>
</body>
</html>
当我输入不在数组中的单词时,如何显示字符串"不在字典中"?我也非常感谢任何关于改进代码的反馈或建议。
PHP 有一个函数,叫做 in_array
。你可以做这样的事情:
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
if(!in_array($word, array_keys($dict))){
echo '"' . $word . '" not found in the dictionary.';
}else{
echo $dict[$word];
}
编辑:改进
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
if(!array_key_exists(strtolower($word), $dict)){
echo '"' . $word . '" not found in the dictionary.';
}else{
echo $dict[$word];
}
更改函数代码
function translate($word){
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
if(array_key_exists($word, $dict)){
echo $dict[$word];
}else{
echo 'not in dictionary';
}
}
如果在找到单词时从函数返回值,否则可以对结果执行逻辑测试以显示备用错误消息。
<form method="post" action="">
<input type="string" name="word">
<input type="submit">
</form>
<?php
if( $_SERVER['REQUEST_METHOD']=='POST' ){
if ( isset( $_POST["word"] ) ) {
$word = $_POST["word"];
echo $word . " -> ";
function translate( $word=false ){
if( $word ){
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
foreach ($dict as $en => $th) {
if( $word == $en ) {
return $th;
}
}
}
return false;
}
$result=translate( $word );
echo $result ? $result : 'Sorry, not found!';
} else {
echo "enter a word";
}
}
?>
您可以使用
array_key_exist:
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
if (array_key_exists($word, $dict)) {
//in dictionary
}else{
//not in dictionary
}
请尝试这个
<form method="post" action="">
<input type="string" name="word">
<input type="submit">
</form>
<?php
function translate($word) {
$dict = array('hello' => 'sawadee khap', 'thanks' => 'kap khum khap', 'sorry' => 'mai pen rai');
if (array_key_exists($word, $dict)) {
echo $dict[$word];
} else {
echo " not in dictionary";
}
}
if (isset($_POST["word"])) {
$word = $_POST["word"];
echo $word . " -> ";
translate($word);
} else {
echo "enter a word";
}
?>
您的顶部 if 语句缺少大括号。
至于你的问题,我假设你想浏览字典,如果没有找到这个词来呼应它。您可以使用标志。将其设置为for循环之前的内容,然后在找到单词时将其设置为其他内容。然后在 for 循环的末尾检查,例如:
$found = false;
foreach ($dict as $en => $th) {
if ($word == $en) {
$found = true'
echo $th;
break;
}
}
if (!$found) echo $word;''