创建参数化 RESTFUL Web 服务时未路由找到错误


not route found error while creating parameterize restful webservice

我正在使用symfony 2.2.3FOSRestBundle来实现Restful网络服务。

这是我的代码,但是当我触发以下URL时,我收到以下错误

No route found for "GET /business/john"

这是控制器代码

use FOS'RestBundle'Controller'Annotations as Rest;
use Symfony'Component'HttpKernel'Exception'NotFoundHttpException;
use Symfony'Component'HttpFoundation'Response;
use Symfony'Component'HttpFoundation'JsonResponse;
use Symfony'Bundle'FrameworkBundle'Controller'Controller;
use Symfony'Component'Security'Core'Exception'AccessDeniedException;
use FOS'RestBundle'Controller'FOSRestController;
use FOS'RestBundle'Routing'ClassResourceInterface;
class BusinessController extends Controller {

        public function getBusinessAction($para){

          return new JsonResponse(array('name' => $para));
        } 
}

这是我的网址

http://localhost/symfony/web/app_dev.php/business/john

这是我的路线

如果我从 url 和函数中删除参数getBusinessAction那么它有效,但不适用于参数/

_business:
    resource: "@HubHomeBundle/Controller/BusinessController.php"    
    type: rest

更新

内部app/confing/routing.yml

   hub_home:
    resource: "@HubHomeBundle/Resources/config/routing.yml"

只是为了确定,这是来自HubHomeBundle/Resources/config/routing.yml吗?

_business:
    resource: "@HubHomeBundle/Controller/BusinessController.php"    
    type: rest

如果是这样,请尝试对其进行编辑并将其更改为:

_business:
    resource: HubHomeBundle'Controller'BusinessController   
    type: rest

"resource"标记的值应该是控制器类的完全限定名称,而不是文件的路径