>主要编辑：重新构建问题，因为这可能更容易解决...
我正在尝试使用Wordpress中的PHP代码生成JSON微数据。我目前正在使用 foreach(( 方法循环浏览页面上的帖子列表，将它们的缩略图、标题和链接数据放入一个数组中，稍后我将对该数组进行编码为 JSON 微数据。但是，我使用 foreach(( 组装的数组并没有按照我想要的方式输出数据。
我花了几个小时试图让这部分数据正确输出，但无济于事。
--
我想要实现的目标(使用 print_r(( 查看和测试我的 PHP 代码( - 例如，而不是像 [0] 这样的索引号。 [1]等等，我希望每个数组输出[associatedMedia]，如下所示：
Array
(
[associatedMedia] => Array
(
[image] => http://www.website.com/thumbnail.jpg
[name] => post title
[url] => http://www.website.com/the-post
)
[associatedMedia] => Array
(
[image] => http://www.website.com/second-thumbnail.jpg
[name] => second post title
[url] => http://www.website.com/the-second-post
)
// And so on...
)
我目前的结果：
Array
(
[0] => Array
(
[image] => http://www.website.com/first-thumbnail.jpg
[name] => first post title
[url] => http://www.website.com/the-post-one
)
[1] => Array
(
[image] => http://www.website.com/second-thumbnail.jpg
[name] => second post title
[url] => http://www.website.com/the-post-two
)
[2] => Array
(
[image] => http://www.website.com/third-thumbnail.jpg
[name] => third post title
[url] => http://www.website.com/the-post-three
) // And so on...
)
我的方法：
// other PHP code
global $post;
global $wp_query;
$category = $wp_query->get_queried_object();
$args = array( 'category' => $category->cat_ID );
$posts = get_posts( $args );
$post_details = array();
$i = 0;
foreach( $posts as $post ) {
setup_postdata($post);
$thumb_url = wp_get_attachment_image_src( get_post_thumbnail_id(),'thumbnail' );
$post_thumbnails['image'] = $thumb_url[0];
$post_titles['name'] = get_the_title();
$post_links['url'] = get_permalink();
$post_details[$i]['image'] = $post_thumbnails['image'];
$post_details[$i]['name'] = $post_titles['name'];
$post_details[$i]['url'] = $post_links['url'];
$i++;
};
wp_reset_postdata();
print_r($post_details);
才刚刚开始进入更高级的编程，我相信我上面的代码看起来很粗糙。因此，有关如何缩短它的任何帮助或提示将不胜感激。
编辑：添加了更多$post相关代码
使用这个
$array_details['associatedMedia'][$i] = $post_details[$i];
而不是
$array_details['associatedMedia'] = $post_details[$i];
更新：
数组元素的键应该是唯一的。使用以下任何格式来获得所需的结果。
foreach( $posts as $post ) {
....
$array_details['associatedMedia'][$i] = $post_details[$i];
i++;
}
结果：
Array
(
['associatedMedia'] => Array(
[0] => Array(
[image] => http://www.website.com/first-thumbnail.jpg
[name] => first post title
[url] => http://www.website.com/the-post-one
)
[1] => Array(
[image] => http://www.website.com/second-thumbnail.jpg
[name] => second post title
[url] => http://www.website.com/the-post-two
)
[2] => Array(
[image] => http://www.website.com/third-thumbnail.jpg
[name] => third post title
[url] => http://www.website.com/the-post-three
) // And so on...
)
)
或
foreach( $posts as $post ) {
....
$array_details[$i]['associatedMedia']= $post_details[$i];
i++;
}
结果：
Array
(
[0] => Array(
['associatedMedia'] => Array(
[image] => http://www.website.com/first-thumbnail.jpg
[name] => first post title
[url] => http://www.website.com/the-post-one
)
)
[1] => Array(
['associatedMedia'] => Array(
[image] => http://www.website.com/second-thumbnail.jpg
[name] => second post title
[url] => http://www.website.com/the-post-two
)
)
[2] => Array(
['associatedMedia'] => Array(
[image] => http://www.website.com/third-thumbnail.jpg
[name] => third post title
[url] => http://www.website.com/the-post-three
)
) // And so on...
)
只需删除 $i++ 即可使用右括号。定义 $i=0对于 foreach 的第一次迭代，它增加到 1。然后分配 $array_details['associatedMedia'] = $post_details[$i]，事实上$array_details['associatedMedia'][0] = $post_details[1];
对不起我的"技术"英语。(:
更新
foreach( $posts as $key => $post ) {
。
$array_details[$key]['associatedMedia'] = $post_details[$i]