偶数和奇数,而在 PHP 中循环


even and odd numbers while loop in php

我想通过这样的while循环制作偶数和奇数

these are even 2,4,6,8,10
these are odd 1,3,5,7,9

我试图用一个 for 循环来制作它:

<?php
    $end=50;
    $even= "Even Numbers Are : ";
    $odd="<br /> Odd Numbers Are : ";
    for($i=1;$i<=$end;$i++)
    {
        if($i%2==0)
        {
            $even.=$i.",";
        }else $odd.=$i.","; 
    }   
    echo $even.$odd;
?>

参加派对有点晚了,但我很友善,无论如何都必须写它

<?php
             $i=0;
             while($i <= 10){
                 if($i % 2 == 0){
                     echo $i." - Even,  ";
                 }else{
                      echo $i." - Odd,  ";
                 }
                 $i++;
             }
   ?>

此外,在for循环中,您不是在打开else而是在关闭它。

这是启动变量的方法:

$i = 0;

这是递增变量 + 1 的方法:

$i = $i + 1;
// or simply
$i++;

这就是while()循环的工作方式:

while([expression here is true]) {
   // do stuff
}

有了这些知识,您可以尝试自己做功课。

文档:

  • http://php.net/manual/en/control-structures.while.php
 class IsOdd
   {
   public function __construct($x) {
    if ($x % 2 != 0) {
     echo "this odd number";
    } else {
     echo "this even number";
    }
   }
   }
  $odd = new IsOdd(5);
//output
this even number
    <?php
echo"Ashutosh Verma Branch_IT_9889313834";
echo"<br />";
echo "Even No between 1 to 30 are:--";
echo"<br />";
for ($x=1; $x<=30; $x++)
{
    if( $x%2==0)
    {
    echo $x.", ";
    }
}
echo "<br />";
echo "Odd No between 1 to 30 are:--";
echo"<br />";
for ($x=1; $x<=30; $x++)
{
    if( $x%2!=0)
    {
    echo $x.", ";
    }
}
?>
---------------------------------------OOTPUT-------------------------------------
Ashutosh Verma Branch_IT_9889313834
Even No between 1 to 30 are:--
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 
Odd No between 1 to 30 are:--
1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29,