如何在php中输入子字符串的第一个和最后一个字符来从字符串中删除子字符串
例如,在字符串"你好,我的名字是约翰"中,如果我输入"n"和"s",它应该返回"你好我的约翰"......请帮忙
/**
* Process function.
* For lack of a better name.
*/
function process($f, $l, $subject)
{
return preg_replace(sprintf('/%s.*?%s/', preg_quote($f), preg_quote($l)), '', $subject);
}
$f = 'n';
$l = 's';
echo process($f, $l, 'Hello my last name is Doe and my first name is John');
输出:
Hello my last Doe at John
我添加了实用程序,但它实际上与preg_replace('/n.*?s/', '', $subject)
相同。
给出你的字符串:
$var = "Hello my name is John";
$sub = getSubString($var,"n","s");
echo $sub;
function getSubString($str,$start,$end) {
if(($pos1=strpos($str,$start))===false)
return $str; // not found
if(($pos2=strpos($str,$end,$pos1))===false)
return $str; // not found
return substr($str,0,$pos1).substr($str,$pos2+1);
}
结果在:
Hello my John
你应该得到第一个和第二个字母的位置,并对方法使用 strpos 作为方法 substr
function my_Cut($string, $first_letter, $second_letter){
$pos[] = strpos($string, $first_letter);
$pos[] = strpos($string, $second_letter);
$result = substr($string, $pos[0] , -($pos[1]-$pos[0]-2));
return str_replace ($result, "", $string);
}
$string = "Hello my name is John";
echo my_Cut($string, "n", "s");
像这样的东西...我认为。