如何使用包含的文件在PHP中设置功能 - How to setup function in PHP with included file

我有3页。我已经include("include/header.php)了HTML网页+导航的开头。当用户在联系人页面上时，导航链接带有下划线text-decoration: underline; 我的问题是：我如何使函数自动更改类 - 当用户转到该页面时.underline？谢谢！

我的标题.php导航代码

<div class="navigation>
<a href="index.php" class="underline">Home<a> <!-- simulating that the user is on this page -->
<a href="about.php">About me</a>
<a href="contact.php">Contact me!</a>
</div>

我的 css 代码

.underline {
text-decoration: underline;
}

索引处的代码.php 和其他包括标头.php

<?php include("include/header.php") ?>

试试这个：

<?php
function underline($page) {
    if (strpos($_SERVER['REQUEST_URI'], $page) !== false) {
        echo "underline";
    }
}
?>
<div class="navigation>
<a href="index.php" class="<?php underline('index.php'); ?>">Home<a> <!-- simulating that the user is on this page -->
<a href="about.php" class="<?php underline('about.php'); ?>">About me</a>
<a href="contact.php" class="<?php underline('contact.php'); ?>">Contact me!</a>
</div>

就个人而言，我对这类事情采取了完全不同的方法。

首先，为您的链接设置一个页面数组，然后循环访问它们，检查它是否是"当前"页面，并添加相关类。

此技术需要更少的代码来输出给定的链接，并且添加更多页面要简单得多。

<?php
$pages = array(
    'Home'        => 'index.php',
    'About me'    => 'about.php',
    'Contact me!' => contact.php'
    // Now adding pages is easy, just add the relevant parts here
);
?>
<div class="navigation">
<?php 
    // Loop over each page from the array
    foreach($pages AS $title => $page) {
        // Set the class depending on which page is current
        $class = (strpos($_SERVER['REQUEST_URI'], $page) !== FALSE) ? 'underline' : '';
        // Output the link
        echo "<a href='{$page}' class='{$class}'>{$title}</a>";
} ?>
</div>

在您的包含/标头.php文件中，使用此...

function is_current($page){
   $current = $_SERVER['PHP_SELF'];
   if($current == $page){
       return ' class="underline"';
    }
 }
<div class="navigation">
<a href="index.php"<?php echo is_current('index.php'); ?>>Home<a> <!-- simulating that the user is on this page -->
<a href="about.php"<?php echo is_current('about.php'); ?>>About me</a>
<a href="contact.php"<?php echo is_current('contact.php'); ?>>Contact me!</a>
</div>

另一个解决方案：

<?php
    function underline($page) {
        return (basename(__FILE__) === $page) ? 'class="underline"' : '';
    }
       ?>
<div class="navigation">
    <a href="index.php" <?php echo underline('index.php') ?>>Home<a>
    <a href="about.php" <?php echo underline('about.php') ?>>About me</a>
    <a href="contact.php" <?php echo underline('contact.php') ?>>Contact me!</a>
</div>

你必须

得到请求的url，你可以为此使用$_SERVER['REQUEST_URI']，你的函数应该看起来像这样

function underlinePage($pageYouWant) {
  if ($_SERVER['REQUEST_URI'] == "/".$pageYouWant)) {
    return 'underline';
  }
}

你像这样调用函数

<div class="navigation>
  <a href="index.php" class="<?= underlinePage('index.php'); ?>">Home<a>
  <a href="about.php" class="<?= underlinePage('about.php'); ?>">About me</a>
  <a href="contact.php" class="<?= underlinePage('contact.php'); ?>">Contact me!</a>
</div>