我尝试了substr((但无法使其工作。我只需要$leadsmissed、$panswerrate和$pcloserate四舍五入到最接近的整数并显示它。我还需要$prevenue显示小数点后两位数字：xxx.xx
我的语法是否缺少某些内容？我对这一切很陌生。任何帮助将不胜感激。谢谢！
<?php
$branches = $_POST['branches'];
$closerate = $_POST['closerate'];
$ticketsize = $_POST['ticketsize'];
$leadsperhour = .87;
$revenue = ($branches * $leadsperhour) * $closerate * $ticketsize;
$leadsmissed = $branches * $leadsperhour;
$panswerrate = .92 * $leadsmissed;
$pcloserate = $closerate * $leadsmissed;
$prevenue = $pcloserate * $ticketsize;
$result['string1'] = "Your company, on average, missed " . $leadsmissed . " leads in the past hour. ";
$result['string2'] = "With Pronexis, you would have talked to " . $panswerrate . " of those leads, closed " . $pcloserate . " of them, and received $" . $prevenue . " more revenue!";
echo json_encode($result);
?>
舍入到最接近的整数：
$leadsmissed = round($leadsmissed);
$panswerrate = round($panswerrate);
$pcloserate = round($pcloserate);
后 2 位的浮点数
$prevenue = number_format($prevenue , 2);