我今天学习php非常糟糕。有人可以告诉我为什么这不起作用吗？我在第 23 行的非对象和未定义变量上调用成员函数(( 时出错这是代码：
<?php
// connect to the MySQL server
$conn = new mysqli('localhost', 'username', 'password', 'Org_db');
// check connection
if (mysqli_connect_errno()) {
exit('Connect failed: '. mysqli_connect_error());
}
//for insert user info into users table columns
$id = '';
$name = 'Bob Grundy';
$pass = md5("secure");
$email = 'bob@acgs.org';
$reg_date = date("m/d/Y");
//line 23
if (!$stmt = $mysqli->prepare("INSERT INTO `users` (`id`, `name`, `pass`, `email`,
`reg_date`) VALUES ( ?,?,?,?,?)")) {
echo "Prepare failed: (" . $mysqli->errno . ") " . $mysqli->error;
}
/* Prepared statement, bind and execute */
if (!$stmt->bind_param("issss", $id, $name, $pass, $email, $reg_date)) {
echo "Binding parameters failed: (" . $stmt->errno . ") " . $stmt->error;
}
if (!$stmt->execute()) {
echo "Execute failed: (" . $stmt->errno . ") " . $stmt->error;
}
?>
您定义了$conn = new mysqli(..但是在使用!$stmt = $mysqli->prepare("..之后，在这里，$mysqli变量应更改为$conn例如：
if (!$stmt = $conn->prepare("INSERT INTO `users` (`id`, `name`, `pass`, `email`,
`reg_date`) VALUES ( ?,?,?,?,?)")) {
echo "Prepare failed: (" . $mysqli->errno . ") " . $mysqli->error;
}