对命令行cURL到PHP脚本调用感到困惑


Confused about command line cURL to PHP script call

我正在尝试将此cURL命令行调用转换为PHP脚本。我读过很多关于它的文章,并尝试了几个选项,但没有一个能够返回结果。下面是命令行调用:

curl -v https://api.sandbox.paypal.com/v1/oauth2/token '
-H "Accept: application/json" '
-H "Accept-Language: en_US" '
-u "EOJ2S-Z6OoN_le_KS1d75wsZ6y0SFdVsY9183IvxFyZp
:EClusMEUk8e9ihI7ZdVLF5cZ6y0SFdVsY9183IvxFyZp" '
-d "grant_type=client_credentials"

这是我到目前为止尝试过的:

$data = "grant_type=client_credentials";
$url = "https://api.sandbox.paypal.com/v1/oauth2/token";
$ch = curl_init();
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_HEADER,true);
curl_setopt($ch,CURLOPT_HTTPHEADER, array("Accept:application/json","Accept-     Language:en_US"));
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); 
curl_setopt($ch, CURLOPT_USERPWD, "[$idclient]:[$sekret]");
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
$result = curl_exec($ch);
curl_close($ch);
echo $result;
var_dump($result);

请帮助我将其转换为PHP脚本调用。

谢谢

$url = 'https://api.sandbox.paypal.com/v1/oauth2/token';
$header_array = array(
    'Accept: application/json',
    'Accept-Language: en_US',
);
$username = 'EOJ2S-Z6OoN_le_KS1d75wsZ6y0SFdVsY9183IvxFyZp';
$password = 'EClusMEUk8e9ihI7ZdVLF5cZ6y0SFdVsY9183IvxFyZp';
$data_string = 'grant_type=client_credentials';
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 5);
curl_setopt($ch, CURLOPT_TIMEOUT, 5);
curl_setopt($ch, CURLOPT_HTTPHEADER, $header_array);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string); 
curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);  
$data = curl_exec($ch);
curl_close($ch);
var_dump($data);