index.php 这是我的索引文件，工作正常。 它的作用是检查用户会话变量并显示当前登录的用户。
<?php
error_reporting(E_ALL ^ E_NOTICE);
session_start();
$username = $_SESSION['username'];
?>
<div id="userinfo">
<?php
if ( $username ) {
echo "welcome <b>$username</b> <a href='logout.php'>Logout</a>";
} else {
echo 'welcome guest please <a href="login.php">Login</a>';
}
?>
</div>
登录表单.php
<?php
error_reporting(E_ALL ^ E_NOTICE);
session_start();
$username = $_SESSION['username'];
?>
<form id='frmlogin' method="post" action="esk.php">
<div id="dialogcontainer">
<div id="dialog">
<h3>Welcome to Talk Login</h3>
<p>Username</p>
<input type="text" id="txtloginusername" name="txtloginusername"/>
<p>Password</p>
<input type="password" id="txtloginpassword" name ="txtloginpassword"/> <br /><br />
<button type="submit">Login</button>
<br>
<br>
<div id="logindisplay" class ="display"></div>
</div>
</div>
</form>
登录.php而不是将消息回显到其他页面，我希望它显示在登录表单上.php这恰好是我的登录表单。
<?php
error_reporting(E_ALL ^ E_NOTICE);
session_start();
$username = $_SESSION['username'];
$user = $_POST['txtloginusername'];
$pass = $_POST['txtloginpassword'];
if ( $user ) {
require ('connect.php');
$query = mysql_query("SELECT * FROM user WHERE username = '$user'");
$numrows = mysql_num_rows( $query );
if ( $numrows == 1 ) {
$row = mysql_fetch_assoc( $query );
$dbpass = $row['password'];
$dbuser = $row['username'];
$dbactive = $row['active'];
if ( $pass == $dbpass ) {
if ( $dbactive == 1 ) {
$_SESSION['username'] = $dbuser;
header("location:index.php"); //"success";
}
} else {
echo "You did not enter the correct password"; //Display this somewhere on loginform.php
}
} else {
echo"Invalid Username"; // //Display this also in loginform.php
}
mysql_close();
} else {
echo "Wrong username"; //this too;
}
?>
Follow the Below Steps
1. use Ajax method to send the request from loginform.php page.
function validUser()
{
$.ajax({
type: "POST",
url: 'esk.php',
data: $('#frmlogin').serialize(),
success: function(data){
$("#logindisplay").append(data);
}
});
}
Step 2. remove submit button and change it to type button.
<input type="button" value="submit" onclick=validUser() />
step 3. remove the action of the form.
step 4. on esk.php page simply echo the message u want to show.
Thats It!!!
您可以将
错误消息传递回登录表单，而不是在登录.php中回显结果。
例如，您可以通过以下方式将"错误的用户名"传递回登录表单：
header('Location: loginform.php?err=Wrong+username');
exit;
在loginform.php中，将这些行添加到要显示错误的位置：
<?php
if(isset($_GET['err'])) { echo '<p>'. $_GET['err'] . '</p>'; }
?>