检查字符串是否包含数组的任何值

分解$value并将其转换为数组，然后在 php 中使用array_intersect()函数检查字符串是否不包含数组的值。使用以下代码

    <?php
    $search=array("<",">","!=","<=",">=");
    $value='name >= vivek ';
    $array = explode(" ",$value);
    $p = array_intersect($search,$array);
    $errors = array_filter($p);
//Check if the string is not empty
    if(!empty($errors)){
    echo "The string contains an value of array";
    }
    else
    {
    echo "The string does not containe the value of an array";
    }
    ?>

在此处测试代码 http://sandbox.onlinephpfunctions.com/code/7e65faf808de77036a83e185050d0895553d8211

希望这对你有帮助

是的，但它需要你重新构建你的代码。

$search = array("<" => 0, ">" => 1,"!=" => 2,"<=" => 3,">=" => 4);
$value = "name => vivek ";
$value = explode(" ", $value);
foreach($value as $val) {
    // search the array in O(1) time
    if(isset($search[$val])) {
       // found a match
    }
}

使用 array_map（） 和 array_filter（）

function cube($n)
{
    $value="name => vivek ";
    return strpos($value, $n);
//return($n * $n * $n);
}
$a = array("<",">","!=","<=",">=");
$value="name => vivek ";
$b = array_map("cube", $a);
print_r($b);
$b = array_filter($b);
print_r($b);

$search  = array("<",">","!=","<=",">=");
$value="name => vivek ";
foreach($value as $searchval) {
  if(strpos($value,  $searchval) == false)
  {
  echo "match not found";
  }
  else
  {
  echo "match found";
  }
}

以下是使用 array_reduce 的解决方案：

<?PHP
function array_in_string_callback($carry, $item)
{
    list($str, $found) = $carry;
    echo $str . " - " . $found . " - " . $str . " - " . $item . "<br/>";
    $found |= strpos($str, $item);
    return array($str, (boolean) $found);
}
function array_in_string($haystack, $needle)
{
    $retVal = array_reduce($needle, "array_in_string_callback", array($haystack, false));
    return $retVal[1];
}
$search=array("<",">","!=","<=",">=");
$value="name >= vivek ";
var_dump(array_in_string($value, $search));
?>

我的第一个倾向是用 array_walk（） 和回调解决问题，如下所示：

<?php
$search=array("<",">","!=","<=",">=");
$value = "name >= vivek ";
function test($item, $key, $str)
{
    if( strpos($str, $item) !== FALSE ) {
        echo "$item found in '"$str'"'n";        
    }
}
array_walk($search, 'test', $value);
// output:
> found in "name >= vivek "
>= found in "name >= vivek "

现场演示：http://3v4l.org/6B0WX

虽然这在没有foreach循环的情况下解决了问题，但它用"什么"而不是"是/否"回答来回答问题。 以下代码直接回答问题，并允许回答"什么"，如下所示：

<?php
function test($x)
{
    $value="name >= vivek ";
    return strpos($value, $x);
}
$search = array("<",">","!=","<=",">=");
$chars = array_filter( $search, "test" );
$count = count($chars);
echo "Are there any search chars? ", $answer = ($count > 0)? 'Yes, as follows: ' : 'No.';
echo join(" ",$chars);
// output:
Are there any search chars? Yes, as follows: > >=

现场演示：http://3v4l.org/WJQ5c

如果响应是否定的，则输出为"否"，后跟一个空格。

与第一个解决方案相比，第二个解决方案的一个关键区别是，在这种情况下，有一个可以操作的返回结果。如果数组的元素与字符串中的字符匹配，则array_filter将该元素添加到$chars。新数组的元素计数回答了问题，数组本身包含任何匹配项（如果希望显示它们）。