如果我有以下PATH
作为string
:
dirname/user folder/sample_file.png
我将如何在 PATH 中的 dirname/user
文件夹之后添加字符串_trash
,因此其结果为:
dirname/user folder_trash/sample_file.png
这应该适合您:
<?php
$path = "dirname/user folder/sample_file.png";
echo $path = dirname($path) . "_trash/" . basename($path);
?>
输出:
dirname/user folder_trash/sample_file.png
编辑:
您可以搜索该文件夹,然后将其替换为新文件夹:
<?php
$path = "dirname/user folder/another folder/sample_file.png";
$searchFolder = "/user folder/";
$replaceFolder = "user folder_trash";
echo $path = preg_replace($searchFolder, $replaceFolder, $path, 1);
?>
输出:
dirname/user folder_trash/another folder/sample_file.png
编辑2:
如果每次刺痛都遵循相同的模式,这应该可以更改第二个文件夹:
<?php
$path = "dirname/user folder/another folder/another folder/sample_file.png";
$parts = explode("/", $path);
$parts[1] = $parts[1] . "_trash";
echo $path = implode("/", $parts);
?>
输出:
dirname/user folder_trash/another folder/another folder/sample_file.png
另一种方式:
-
您还可以使用
explode
函数将字符串拆分为项目(使用count
获取项目数的函数)。 -
然后修改每个项目。这取决于你。
-
最后,按
string concatenation
将项目合并为字符串