我定义了以下数组：
array(
'name'=>'Blue',
'age'=>'0',
'skin'=>array(
'White Skin','Tanned Skin'
),
'eye'=>array(
'Black','Brown','Honey'
),
'personality'=>array(
'Intelligent','Warm','Trustworthy','Sweet'
),
'ocassion'=>array(
'Every day wear','Celebrations','Restaurant Dinner','Feasts','Visiting friends'
),
'hair'=>'All Colors',
'style'=>array(
'Loved to be admired','Center of attention'
),
'description'=>'Blue lens are perfect for any..'
);
我正在尝试从 HTML 表单到此数组中查找匹配数。从 HTML 表单以数组格式返回的可能结果是：
Array
(
[age] => 16
[skin] => Tanned Skin
[eye] => Brown
[personality] => Array
(
[0] => Intelligent
[1] => Warm
[2] => Trustworthy
)
[ocassion] => Weddings
[hair] => Dark Brown
[style] => Array
(
[0] => Style Queen
[1] => Testing val
)
)
我尝试通过第一个数组的每个键进行迭代，但未能实现我想要的，我也尝试使用函数array_intersect_assoc($stack,$search)但似乎找不到确切的匹配项，因为$search数组（第二个示例）有一些字符串类型的键=>值对，并且它无法将任何出现匹配到第一个数组中，因为该值实际上是一个数组， 而不是字符串。
有人可以指出我一个想法，或者可以让我知道在这里最好做什么吗？
在过去的 3 小时内，我尝试了很多东西，但没有成功。
好的，那这个怎么样。源数据：
$demands = array(
'name'=>'Blue',
'age'=>'0',
'skin'=>array(
'White Skin','Tanned Skin'
),
'eye'=>array(
'Black','Brown','Honey'
),
'personality'=>array(
'Intelligent','Warm','Trustworthy','Sweet'
),
'ocassion'=>array(
'Every day wear','Celebrations','Restaurant Dinner','Feasts','Visiting friends'
),
'hair'=>'All Colors',
'style'=>array(
'Loved to be admired','Center of attention'
),
'description'=>'Blue lens are perfect for any..'
);
$possible_match = array(
'age'=>'16',
'skin'=>'Tanned Skin',
'eye'=>'Brown',
'personality'=>array(
'Intelligent','Warm','Trustworthy'
),
'ocassion'=>array(
'Weddings'
),
'hair'=>'Dark Brown',
'style'=>array(
'Style Queen','Testing value'
)
);
而匹配算法：
$result = array();
$count_matches = 0;
// Go through all the demands
foreach ($demands as $key => $value){
// If there's a matching key in the possible match array
if (isset($possible_match[$key])){
// If there are more demanded values
if (is_array($value)){
// Let all demanded values be lowercase
$value = array_map('strtolower', $value);
// If there are more possible matching values
if (is_array($possible_match[$key])){
// Let all possibly matching values be lowercase, too
$possible_match[$key] = array_map('strtolower', $possible_match[$key]);
// And then do the intersect.
$intersect = array_intersect($value, $possible_match[$key]);
if ($intersect){
// If that intersect is not empty, add that to the resulting array
$result[$key] = $intersect;
$count_matches += count($intersect);
};
} else {
// If there's only one possible matching value, search that
// value in the demaned array
if (in_array(strtolower($possible_match[$key]), $value, true)){
// And add it to the results
$result[$key][] = strtolower($possible_match[$key]);
$count_matches++;
}
}
} else {
if (is_array($possible_match[$key])){
// If there are more possible matching values but the demand is a string,
// find that string in those possible values
$possible_match[$key] = array_map('strtolower', $possible_match[$key]);
if (in_array(strtolower($value), $possible_match[$key], true)){
// And add it to the results
$result[$key] = $value;
$count_matches++;
}
} else {
// If the demanded value is only one (= it's a string and not an array)
// and the possible match is also a string, do a lowercase compare
// + if there's a word "all" in the demanded value, pass it at all times ;D
if (strtolower($possible_match[$key]) == strtolower($value)
|| stripos($value, "all") !== false){
// And add it to the resulting array
$result[$key] = strtolower($value);
$count_matches++;
}
}
}
}
}
var_dump ($result);
var_dump ($count_matches);
可能会有一些优化的机会，但基本思想应该在那里:)
结果：
array (size=4)
'skin' =>
array (size=1)
0 => string 'tanned skin' (length=11)
'eye' =>
array (size=1)
0 => string 'brown' (length=5)
'personality' =>
array (size=3)
0 => string 'intelligent' (length=11)
1 => string 'warm' (length=4)
2 => string 'trustworthy' (length=11)
'hair' => string 'all colors' (length=10)
加上计数，如果您愿意：
int 6