问题是我想从具有内部连接和 where 条件的不同表中获取所有字段。我试过这个查询
$nowfire="select *
from reg_user r
inner join state s
on r.state=s.state_id
inner join country c
on r.country= c.country_id
where email_id='xyz@gmail.com'";
我知道另一种方法是这样的
$nowfire="select r.profile_id, r.email_id,s.state_name, c.city_name
from reg_user r
inner join state s
on r.state=s.state_id
inner join country c
on r.country= c.country_id
where email_id='xyz@gmail.com'";
这是工作...没关系。但我可以像上面一样使用吗 * 选择 * * ....格式。。。这在 Mysqli 中可能吗?请帮忙提前感谢任何帮助.....
你可以试试:
$nowfire="select r.*,s.state_name, c.city_name
from reg_user r
inner join state s
on r.state=s.state_id
inner join country c
on r.country= c.country_id
where email_id='xyz@gmail.com'";
$nowfire="select r.*,s.*, c.*
from reg_user r
inner join state s
on r.state=s.state_id
inner join country c
on r.country= c.country_id
where email_id='xyz@gmail.com'";