将字符串拆分为两个变量 - 未定义不是一个函数 - Split string into two variables - getting undefined is not a function

Split string into two variables - getting undefined is not a function

我正在使用一个内部带有foreach循环的for循环。在foreach循环中，我获取了我需要的信息并将其回显到如下所示的字符串中：19:00^-2,2° C。我想把时间（19:00）放在一个变量中，把温度（-2,2° C）放在另一个变量中，这样我就可以把它们用在图表上。但我不知道我该如何拼接这两者。这是它目前的样子：

var yr = localStorage.yr.split('|');
time = yr[16].split('~');
temp = time.split('^');
lineChartData = {
    labels: time,
    datasets: [{
        label: "My Second dataset",
        fillColor: "rgba(151,187,205,0.2)",
        strokeColor: "rgba(151,187,205,1)",
        pointColor: "rgba(151,187,205,1)",
        pointStrokeColor: "#fff",
        pointHighlightFill: "#fff",
        pointHighlightStroke: "rgba(151,187,205,1)",
        data: temp
    }]
}

有了这段代码，我Uncaught TypeError: undefined is not a function temp = time.split('^');. yr[16]打印以下内容：

19:00^-2,2° C~20:00^-2° C~21:00^-2° C~22:00^-1,9° C~23:00^-1,6° C~00:00^-1,5° C~01:00^-1,3° C~02:00^-1,1° C~03:00^-0,9° C~04:00^-0,9° C~05:00^-1,1° C~06:00^-1,3° C~07:00^-1,6° C~

PHP代码如下所示：

for($i = 0; $i < 13; $i++) {
    $datetime           = date('Y-m-d'TH', strtotime('+'.$i.' hour'));
    $forecast_period    = $forecast->xpath('(//product/time[contains(@datatype, "forecast")][contains(@from, "'.$datetime.':00:00Z")][contains(@to, "'.$datetime.':00:00Z")])');
    foreach($forecast_period AS $period) {
        $period_datetime                    = date('H:i', strtotime($period->attributes()->from));
        $period_temperature             = $period->location->temperature->attributes()->value;
        $period_temperature_dewpoint        = $period->location->dewpointTemperature->attributes()->value;
        $period_temperature_unit            = $period->location->temperature->attributes()->unit;
        $period_wind_direction              = $period->location->windDirection->attributes()->name;
        $period_wind_direction_degrees      = $period->location->windDirection->attributes()->deg;
        $period_wind_speed                  = $period->location->windSpeed->attributes()->mps;
        $period_fog                     = $period->location->fog->attributes()->percent;
        $period_cloudiness                  = $period->location->cloudiness->attributes()->percent;
        $period_cloudiness_low              = $period->location->lowClouds->attributes()->percent;
        $period_cloudiness_medium           = $period->location->mediumClouds->attributes()->percent;
        $period_cloudiness_high         = $period->location->highClouds->attributes()->percent;
        $period_pressure                    = $period->location->pressure->attributes()->value;
        $period_pressure_unit               = $period->location->pressure->attributes()->unit;
        $period_humidity                    = $period->location->humidity->attributes()->value;
        echo $period_datetime.'^'.temp($period_temperature, $period_temperature_unit, 'not-normal').'~';
    }
}

我通过 simplexml_load_file() 从 YR 的 API 获取信息（$forecast是使用 simplexml_load_file() 从 API 获取 XML 数据的人）。

话虽如此，这是我的问题：如何将yr[16]的时间和温度放入两个变量而不会出错，从而构建图表？

您可以使用Array.prototype.map：

var time_and_temp = time.map(function(el) {
    var temp = el.split('^');
    return { time: temp[0], temperature: temp[1] };
});

这会将time_and_temp设置为如下数组：

[ { time: "19:00",
    temperature: "-2,2° C"
  },
  { time: "20:00",
    temperature: "-2° C"
  }
  ...
]

yr16 = yr[16].toString();

time = yr16.split('^')[0];

temp = yr16.split('^')[1];

您需要在.split('^')后包含[0]和[1]，以指示哪个部分（在^之前或之后）被分配给变量。