>我在下面有一个字符串
$string = ot>4>om>6>we>34>ff>45
我希望 JSON 输出是这样的
[{"name":"website","data":["ot","om","we","ff"]}]
和
[{"name":"websitedata","data":["4","6","34","45"]}]
我尝试过什么
$query = mysql_query("SELECT month, wordpress, codeigniter, highcharts FROM project_requests");
$category = array();
$category['name'] = 'website';
$series1 = array();
$series1['name'] = 'websitedata';
while($r = mysql_fetch_array($query)) {
$category['data'][] = $r['month'];
}
$result = array();
array_push($result,$category);
array_push($result,$series1);
print json_encode($result, JSON_NUMERIC_CHECK);
但是上面的代码仅适用于 MySQL 表中的数据存在于行中，我想要的是使用上述字符串中的数据获得相同的结果。
$string = ot>4>om>6>we>34>ff>45
新更新：
我想修改相同的字符串
$string = ot>4>om>6>we>34>ff>45
到
JSON 输出：
[
{
"type" : "pie",
"name" : "website",
"data" : [
[
"ot",
4
],
[
"om",
6
],
[
"we",
34
]
]
}
]
我已经更新了答案，请检查json部分，我想要php代码。问候
您可以在> s上explode()，然后遍历元素：
$string = "ot>4>om>6>we>34>ff>45";
$array1 = [
'name'=>'website',
'data'=>[]
]
$array2 = [
'name'=>'websitedata',
'data'=>[]
]
foreach(explode('>', $string) as $index => $value){
if($index & 1) //index is odd
$array2['data'][] = $value;
else //index is even
$array1['data'][] = $value;
}
echo json_encode($array1); //prints {"name":"website","data":["ot","om","we","ff"]}
echo json_encode($array2); //prints {"name":"websitedata","data":["4","6","34","45"]}
使用preg_match_all()的解决方案：
$string = "ot>4>om>6>we>34>ff>45";
preg_match_all('/('w+)>('d+)/', $string, $matches);
$array1 = [
'name'=>'website',
'data'=> $matches[1]
];
$array2 = [
'name'=>'websitedata',
'data'=> $matches[2]
];
echo json_encode($array1); //prints {"name":"website","data":["ot","om","we","ff"]}
echo json_encode($array2); //prints {"name":"websitedata","data":["4","6","34","45"]}
更新：
要获取所需的第二种类型的数组，请使用以下命令：
//since json_encode() wraps property names in double quotes (which prevents the chart script from working), you'll have to build the json object manually
$string = "ot>4>om>6>we>34>ff>45";
preg_match_all('/('w+)>('d+)/', $string, $matches);
$data = [];
foreach($matches[1] as $index => $value){
if(isset($matches[2][$index]))
$data[] = '["' . $value . '",' . $matches[2][$index] . ']';
}
$type = 'pie';
$name = 'website';
echo $jsonString = '[{type:"' . $type . '",name:"' . $name . '",data:[' . implode(',', $data) . ']}]'; // prints [{type:"pie",name:"website",data:[["ot",4],["om",6],["we",34],["ff",45]]}]
更新#2：
此代码使用 explode() ，虽然它可能不是最有效的方法，但它是有效的。
//since json_encode() wraps property names in double quotes (which prevents the chart script from working), you'll have to build the json object manually
$string = "ot>4>om>6>we>34>ff>45";
$keys = [];
$values = [];
foreach(explode('>', $string) as $key => $value){
if(!($key & 1)) //returns true if the key is even, false if odd
$keys[] = $value;
else
$values[] = $value;
}
$data = [];
foreach($keys as $index => $value){
if(isset($values[$index]))
$data[] = '["' . $value . '",' . $values[$index] . ']';
}
$type = 'pie';
$name = 'website';
echo $jsonString = '[{type:"' . $type . '",name:"' . $name . '",data:[' . implode(',', $data) . ']}]'; // prints [{type:"pie",name:"website",data:[["ot",4],["om",6],["we",34],["ff",45]]}]
这应该有效，尽管可能有更好的方法可以做到这一点。
$string = "ot>4>om>6>we>34>ff>45";
$website = ["name" => "website", "data" => []];
$websiteData = ["name" => "websitedata", "data" => []];
foreach(explode(">", $string) as $i => $s) {
if($i % 2 === 0) {
$website["data"][] = $s;
} else {
$websiteData["data"][] = $s;
}
}
echo json_encode($website);
echo json_encode($websiteData);
正则表达式替代方案：
preg_match_all("/([a-z]+)>('d+)/", $string, $matches);
$website = ["name" => "website", "data" => $matches[1]];
$websiteData = ["name" => "websitedata", "data" => $matches[2]];
试试这段代码：
$string = 'ot>4>om>6>we>34>ff>45';
$string_split = explode('>', $string);
$data = array("name" => "website");
$data2 = $data;
foreach ($string_split as $key => $value)
{
if (((int)$key % 2) === 0)
{
$data["data"][] = $value;
}
else
{
$data2["data"][] = $value;
}
}
$json1 = json_encode($data, JSON_NUMERIC_CHECK);
$json2 = json_encode($data2, JSON_NUMERIC_CHECK);
echo $json1;
echo $json2;
输出：
{"name"："website"，"data"：["ot"，"om"，"we"，"ff"]}
{"name"："website"，"data"：[4，6，34，45]}
问候。
试试这个片段：
$strings = explode('>', 'ot>4>om>6>we>34>ff>45');
// print_r($string);
$x = 0;
$string['name'] = 'website';
$numbers['name'] = 'websitedata';
foreach ($strings as $s)
{
if ($x == 0) {
$string['data'][] = $s;
$x = 1;
} else {
$numbers['data'][] = $s;
$x = 0;
}
}
print_r(json_encode($string));
echo "<br/>";
print_r(json_encode($numbers));
像往常一样 - 它冗长，但显示了获得所需输出的所有步骤。
<?php //https://stackoverflow.com/questions/27822896/need-help-php-to-json-array
// only concerned about ease of understnding not code size or efficiency.
// will speed it up later...
$inString = "ot>4>om>6>we>34>ff>45";
$outLitRequired = '[{"name":"website","data":["ot","om","we","ff"]}]';
$outValueRequired = '[{"name":"websitedata","data":["4","6","34","45"]}]';
// first: get a key / value array...
$itemList = explode('>', $inString);
/* debug */ var_dump(__FILE__.__LINE__, $itemList);
// outputs ------------------------------------
$outLit = array();
$outValue = array();
// ok we need to process them in pairs - i like iterators...
reset($itemList); // redundant but is explicit
// build both output 'data' lists
while (current($itemList)) {
$outLit[] = current($itemList);
next($itemList); // advance the iterator.
$outValue[] = current($itemList);
next($itemList);
}
/* debug */ var_dump(__FILE__.__LINE__, $itemList, $outLit, $outValue);
// make the arrays look like the output we want...
// we need to enclose them as arrays to get the exact formatting required
// i do that in the 'json_encode' statements.
$outLit = array('name' => 'website', 'data' => $outLit);
$outValue = array('name' => 'websitedata', 'data' => $outValue);
// convert to JSON.
$outLitJson = json_encode(array($outLit));
$outValueJson = json_encode(array($outValue));
// show required and calculated values...
/* debug */ var_dump(__FILE__.__LINE__, 'OutLit', $outLitRequired, $outLitJson);
/* debug */ var_dump(__FILE__.__LINE__, 'OutValue', $outValueRequired, $outValueJson);