更改正则表达式模式与函数返回值匹配 - Change regex pattern matches with function return value

Change regex pattern matches with function return value

我有以下变量：

$text = 'This is a sentence [url=http://site.com] that contains urls [url=javascript:alert();]';

以及用于验证 URL 的以下代码行：

$text = preg_replace('/'[url=([^'']]+)]/', filter_var('$1', FILTER_VALIDATE_URL), $text);

输出：

"这是一个包含网址的句子"

如何获得以下内容作为输出？

"这是一个包含网址的句子 http://site.com"

$text = 'This is a sentence [url=http://site.com] that contains urls [url=javascript:alert();]';
$text = preg_replace_callback(
    '/'[url=([^'']]+)]/',
    function ($url) {
        $clean = filter_var($url[1], FILTER_VALIDATE_URL);
        if ($clean) {
            return '<a href="' . $clean . '">' . $clean . '</a>';
        } else {
            return "";
        }
    },
    $text
);

请参阅 http://codepad.viper-7.com/Hwgq90

<?php
$text = 'This is a sentence [url=http://site.com] that contains urls [url=javascript:alert();]';

function url($url){
    if(filter_var($url, FILTER_VALIDATE_URL))
        return $url;
    return '';
}

$text = preg_replace('/'[url=([^'']]+)]/e', 'url("$1")', $text);

echo $text;