我的一个朋友目前没有在这个脚本上提供大量帮助,我目前正在更新我的旧脚本,但它会显示以下错误消息;
致命错误:调用未定义的方法 mysqli_stmt::bind_params()
$stmt = $db->prepare( $sql );
if (!$stmt)
{
die("Failed to prepare statement: " . $sql);
}
// here I only get the title, website, and summary from the <form>
// that posted to this page:
$title = $_POST["news_title"];
$img = $_POST["news_imgPath"];
$desc = $_POST["news_content"];
$more = $_POST["news_websitePath"];
$stmt->bind_params("ssss", $title, $img, $desc, $more );
if ( ! $stmt->execute() )
{
die("Execution of bound statement failed: " . $stmt->error);
}
echo "Inserted {$stmt->affected_rows} correctly.<hr/>";
$db->close();
致命错误:调用未定义的方法 mysqli_stmt::bind_params()
bind_param,而不是bind_params()
^
你拼错了bind_param
$stmt->bind_param("ssss", $title, $img, $desc, $more );