这是用于发送数据的按钮
<a href="#myModal" data-toggle="modal" id="78" data-target="#edit-modal"> <button type="button" >
<i class="glyphicon glyphicon-zoom-in"></i>
</button></a>
此代码显示数据
<?php echo $er="<div class='"modal-body edit-content'"></div>"; ?>
我想$er下面查询
<?php
$str = "SELECT * FROM examquestion WHERE EQ_ID = '$er' ";
$Recordset7 = mysql_query($str) or die(mysql_error());
$row_Recordset7 = mysql_fetch_assoc($Recordset7);
echo $row_Recordset7['EQ_ID']; ?>
脚本
<script>
$('#edit-modal').on('show.bs.modal', function(e) {
var $modal = $(this),
Id = e.relatedTarget.id;
$modal.find('.edit-content').html(Id);
})
</script>
您可以使用 AJAX 执行此操作。了解这些：
http://www.w3schools.com/ajax/
http://php.net/manual/en/mysqli.quickstart.prepared-statements.php
预准备语句将使您免受 SQL 注入攻击。练习在执行具有用户输入的查询时专门使用它。
.HTML
<a href="#myModal" data-toggle="modal" id="78" class='get-content' data-target="#edit-modal">
<button type="button">
<i class="glyphicon glyphicon-zoom-in"></i>
</button>
</a>
<div id="edit-modal">
<div class="modal-body edit-content"></div>
</div>
PHP （content.php） Using procedure mysql
<?php
$er = $_POST['id'];
$str = "SELECT * FROM examquestion WHERE EQ_ID = '$er' ";
$Recordset7 = mysql_query($str) or die(mysql_error());
$row_Recordset7 = mysql_fetch_assoc($Recordset7);
echo $row_Recordset7['EQ_ID'];
?>
PHP 使用 OOP mysqli （预准备语句）
$mysqli = new mysqli("localhost", "user", "password", "database");
$query = "SELECT content FROM examquestion WHERE EQ_ID = ?";
if ( $stmt = $mysqli->prepare($query) )
{
$stmt->bind_param("s", $er);
if ( $stmt->execute() )
{
$stmt->bind_result($content);
while ($stmt->fetch()) {
echo $content;
}
}
$stmt->close();
}
.JS
<script>
$('a.get-content').click(function() {
var contentId = $(this).attr('id');
var modalId = $(this).attr('data-target');
$.ajax({
url: "content.php",
type: "POST",
data: {id: contentId},
dataType: "html",
success:function(data){
$(modalId).find('.edit-content').eq(0).html(data);
}
});
});
</script>