我当前的PHP代码是：
$searchFor="Sum";
$handle=@fopen("assets/lib/basic.lib"); //this if my file consisting of sum structure
if($handle){
while(!feof($handle)){
$buffer=fgets($handle);
if(strpos($buffer,$searchFor)!==FALSE)
$matches[]=$buffer;
}
fclose($handle);
}
这是basic.lib文件：
Sum: start
Sum: op1 =
Sum: op2 +
Sum: op *
Sum: end
Sub: start
Sub: op1 =
Sub: op2 -
Sub: end
上面的php代码有助于检索所有具有子字符串sum的行
但我想将basic.lib文件重新设计为：
Sum:start
output 1: Hello
output 2: world
Sum:end
Sub:start
output 1: Hello
output 2: Again
Sub:end
那么我现在如何在 $matches 数组中处理 Sum：start 和 Sum：end 之间的行。
提前致谢
具有
file函数的简单解决方案：
$arr = file("assets/lib/basic.lib");
$capture = false;
$needed_lines = [];
foreach ($arr as $line) {
if (strpos($line, "Sum:start") !== false){
$capture = true;
continue;
} elseif (strpos($line, "Sum:end") !== false) {
$capture = false;
}
if ($capture){
$needed_lines[] = $line;
}
}
var_dump($needed_lines);
// the output:
array (size=2)
0 => string 'output 1: Hello
' (length=17)
1 => string 'output 2: world
' (length=17)
您可以将文本文件拆分为数组并检查每个元素中的特定字符串：
$filename = "txtfile.txt";
$handle = fopen($filename, "r");
$contents = fread($handle, filesize($filename));
fclose($handle);
$arr = explode(PHP_EOL, $contents);
foreach ($arr as $key => $value) {
if (strpos($value, ':start') !== false || strpos($value, ':end') !== false) {
unset($arr[$key]);
}
}
$arr = array_values($arr);
print_r($arr);
输出为：
Array
(
[0] => output 1: Hello
[1] => output 2: world
)