我想把我的桌子分成两部分即每侧 15 行。这可能吗？我也试过jQuery了还是没用:(
$conn = new mysqli('localhost', '', '', 'test');
if ($conn->connect_error)
{
die("Connection failed: " . $conn->connect_error);
}
$sql="SELECT dateofattendance,timeofattendance, status,timeofdeparture FROM attendance Where emp='$name'";
$result = $conn->query($sql);
if ($result->num_rows > 0)
{
echo "<table class='table table-condensed table-bordered table-hover'><thead> <tr><th> Date </th><th>IN</th><th>OUT</th><th>Status</th></tr></thead>";
// output data of each row
while($row = $result->fetch_assoc())
{
echo "<tbody><tr class='warning'><td>" . $row["dateofattendance"]. "</td><td>" . $row["timeofattendance"]. "</td><td>" . $row["timeofdeparture"]. "</td><td>" . $row["status"]."</td></tr></tbody></table>";
您已有的代码会将数据输出到单个表中
if($counter<15)
{
echo "<table id='my' class='table table-condensed table-bordered table-hover'><thead> <tr><th > Date </th><th>IN</th><th>OUT</th><th>Status</th></tr></thead>";
// This is the problem. The line below will not stop after 15 rows
// it will run until all data is retrieved. Incrementing the counter
// does not matter at this point because we're already inside the if statement
while($row = $result->fetch_assoc())
{
// this is also wrong. you are declaring a new tbody element for each row
// tbody should be declared once, with the table declaration
echo "<tbody><tr class='warning'><td>" . $row["dateofattendance"]. "</td><td>" . $row["timeofattendance"]. "</td><td>" . $row["timeofdeparture"]. "</td><td>" . $row["status"]."</td></tr></tbody>";
}
echo "</table>";
$counter++;
}
else
{
// also you can't give both tables an id of 'my'. ids must be unique
echo "<table id='my' class='table table-condensed table-bordered table-hover'><thead> <tr><th > Date </th><th>IN</th><th>OUT</th><th>Status</th> </tr></thead>";
...
}
if 语句需要位于 while 语句内。请尝试此代码。
// create wrapper table
echo "<table><tbody><tr></td>";
// create the opening table
echo "<table id='my1' style='float:left;' class='table table-condensed table-bordered table-hover'><thead> <tr><th> Date </th><th>IN</th><th>OUT</th><th>Status</th></tr></thead><tbody>";
while($row = $result->fetch_assoc())
{
// create the row
echo "<tr class='warning'><td>" . $row["dateofattendance"]. "</td><td>" . $row["timeofattendance"]. "</td><td>" . $row["timeofdeparture"]. "</td><td>" . $row["status"]."</td></tr>";
$counter++;
// when the counter is 15, close this table and open another
if($counter == 15)
{
echo "</td><td>"; // move to the next cell in our wrap table
echo "</tbody></table>";
echo "<table id='my2' style='float:left;' class='table table-condensed table-bordered table-hover'><thead> <tr><th> Date </th><th>IN</th><th>OUT</th><th>Status</th></tr></thead><tbody>";
}
}
// close the last table
echo "</tbody></table>";
// close our wrapper table
echo "</td></tr></tbody></table>";
这将输出两个表，每个表有 15 行，它们彼此并排浮动
想知道这是否有效
if ($result->num_rows > 0)
{
echo "<table class='table table-condensed table-bordered table-hover'><thead> <tr><th> Date </th><th>IN</th><th>OUT</th><th>Status</th></tr></thead><tbody>";
// output data of each row
while($row = $result->fetch_assoc())
{
echo "<tr class='warning'><td>" . $row["dateofattendance"]. "</td><td>" . $row["timeofattendance"]. "</td><td>" . $row["timeofdeparture"]. "</td><td>" . $row["status"]."</td></tr>";
}
echo "</tbody></table>";
}
我认为问题出在您的第一个 while 条件中，它将解析所有获取的结果，第二个条件是无用的。
尝试用这个更新你的代码，它可能会起作用
if ($result->num_rows > 0)
{
while($row = $result->fetch_assoc())
{
if($counter == 14)
{
echo "</tbody></table>";
}
else if($counter ==0 || $counter == 14)
{
echo "<table id='my' class='table table-condensed table-bordered table-hover'><thead> <tr><th > Date </th><th>IN</th><th>OUT</th><th>Status</th></tr></thead><tbody>";
}
echo "<tr class='warning'><td>" . $row["dateofattendance"]. "</td><td>" . $row["timeofattendance"]. "</td><td>" . $row["timeofdeparture"]. "</td><td>" . $row["status"]."</td></tr>";
$counter++;
}
echo "</table>";
}