每当我尝试调用函数 Createuser() 时,它都会给我这个错误
致命错误:在字符串上调用成员函数 Createuser()
我真的不知道为什么,因为我的其他功能都可以工作。
我调用函数的代码:
$u = $_POST['username'];
$p = $_POST['password'];
$e = $_POST['email'];
// attempt to create user
$reg = $u->Createuser($u, $p, $e);
// if an error code is sent back, it will put it in a session.
switch ($reg)
{
case 2:
$_SESSION['err'] = 2;
break;
case 3:
$_SESSION['err'] = 3;
break;
case 10:
$_SESSION['err'] = 10;
break;
以及函数本身:
function Createuser($username, $password, $email)
{
include("connection.php");
$info = mysqli_query($db2, "SELECT * FROM users WHERE username = '$username' AND password = '$password'");
// If any field is not empty
if(($username != NULL) && ($password != NULL) && ($email != NULL))
{
// If the result matches break the process
if(mysqli_num_rows($info) == 0)
{
// If rank is defined make it rank 0 else rank equels rank
if($rank == NULL)
{
$rank = 0;
}
else
{
$rank = $rank;
}
// Insert into $table
if(mysqli_query($db2, "INSERT INTO users VALUES(NULL, '$username', '$password', '$email', 0)"))
{
return 10;
}
}
else
{
// Return error code 3
return 3;
}
}
else
{
// Return error code 2
return 2;
}
}
我真的希望有人能帮助我解决这个问题。
您遇到的问题来自以下代码部分:
$u = $_POST['username'];
$p = $_POST['password'];
$e = $_POST['email'];
// attempt to create user
$reg = $u->Createuser($u, $p, $e);
您必须通过$_POST['username']
将$u
设置为字符串,然后尝试在该字符串上调用函数。
如果您之前创建了一个变量$u
该变量是类 User(如注释中所述),则通过执行$u = $_POST['username'];
,您已经销毁了该对象并将其设置为字符串。
您需要执行以下操作:
$user = new User(); // or however the user object is created
$u = $_POST['username'];
$p = $_POST['password'];
$e = $_POST['email'];
// attempt to create user
$reg = $user->Createuser($u, $p, $e);
$reg = $u->Createuser($u, $p, $e);
将其替换为 $reg=$user->Createuser($u, $p, $e); 更改对象的名称。
$u可
验证在此代码中是冲突的。请再拿一个可验证的:
替换此:
$u = $_POST['username'];
跟
$username = $_POST['username'];