像这样在数组中添加缺失日期的最简单方法是什么？它需要按正确的顺序排列，并且由于数据无法添加到关联数组中array_slice()我没有找到一种方法来做到这一点，而不会以四个 foeach 循环结束转换为多维数组并转换回来。谢谢！
Array
(
[1.1.2016] => 10
[3.1.2016] => 5
[5.1.2016] => 8
[8.1.2016] => 3
)
Array
(
[1.1.2016] => 10
[2.1.2016] => 0
[3.1.2016] => 5
[4.1.2016] => 0
[5.1.2016] => 8
[6.1.2016] => 0
[7.1.2016] => 0
[8.1.2016] => 3
)
使用 DateTime 的DatePeriod我们可以循环访问日期，如果日期的开始顺序正确。如果它们的开始顺序可能不正确，则必须编辑开始和结束DateTime
<?php
$newarray = array(); //Our new array
$myarray = array(...); //$myarray is your array that you have
reset($myarray); //Sets array position to start
$key = key($myarray); //Grabs the key
$begin = new DateTime( $key ); //Sets the begin date for period to $begin
end($myarray); //Sets array to end key
$key = key($myarray); //Gets end key
$end = new DateTime($key); //Sets end variable as last date
$end = $end->modify( '+1 day' ); //Includes the last day by adding + 1 day
$interval = new DateInterval('P1D'); //Increases by one day (interval)
$daterange = new DatePeriod($begin, $interval ,$end); //Gets the date range
foreach($daterange as $date){
$date = $date->format("j.n.Y");
if(isset($myarray[$date]))
$newarray[$date] = $myarray[$date];
else
$newarray[$date] = 0;
}
?>
无论日期的顺序如何，这都有效，尽管您可能仅限于一年：
$dates = array("8.1.2016" => 100, "2.1.2016" => 5);
$date = "1.1.2016";
$m = null;
$fixed_dates = array();
while($m <= "12"){
$fixed_dates[$date] = (isset($dates[$date]) ? $dates[$date] : 0);
$edate = explode(".",$date);
$m = $edate[0]+1;
$date = implode(".",array($m,$edate[1],$edate[2]));
}
print_r($fixed_dates);