我有问题。在我的函数中,return 仅显示来自服务器的第一个播放器。我想显示服务器中的所有玩家,但我无法让它工作。这是我的代码:
function players() {
require_once "inc/SampQueryAPI.php";
$query = new SampQueryAPI('uh1.ownserv.pl', 25052); // Zmień dane obok! //
if($query->isOnline())
{
$aInformation = $query->getInfo();
$aServerRules = $query->getRules();
$aPlayers = $query->getDetailedPlayers();
if(!is_array($aPlayers) || count($aPlayers) == 0)
{
return 'Brak graczy online';
}
else
{
foreach($aPlayers as $sValue)
{
$playerid = $sValue['playerid'];
$playername = htmlentities($sValue['nickname']);
$playerscore = $sValue['score'];
$playerping = $sValue['ping'];
return '<li>'.$playername.' (ID: '.$playerid.'), Punkty ('.$playerscore.'), Ping ('.$playerping.')</li>';
}
}
}
}
你从循环中返回。
相反,您应该连接每次迭代的结果,然后在循环外部返回该串联字符串。
例如
$result = "";
foreach($aPlayers as $sValue) {
# add to $result...
}
return $result
function players() {
require_once "inc/SampQueryAPI.php";
$query = new SampQueryAPI('uh1.ownserv.pl', 25052); // Zmień dane obok! //
if($query->isOnline())
{
$aInformation = $query->getInfo();
$aServerRules = $query->getRules();
$aPlayers = $query->getDetailedPlayers();
if(!is_array($aPlayers) || count($aPlayers) == 0)
{
return 'Brak graczy online';
}
else
{
$ret = '';
foreach($aPlayers as $sValue)
{
$playerid = $sValue['playerid'];
$playername = htmlentities($sValue['nickname']);
$playerscore = $sValue['score'];
$playerping = $sValue['ping'];
$ret .= '<li>'.$playername.' (ID: '.$playerid.'), Punkty ('.$playerscore.'), Ping ('.$playerping.')</li>';
}
return $ret;
}
}
}
在一个函数中,你只能返回一个值。
尝试创建玩家列表,并在所有记录都添加到列表中后返回该列表。在您的情况下,玩家列表将产生一系列玩家