MySQL 在一个语句中从两个表中选择两列


mysql selecting two columns from two tables in one statement

我一直在寻找SO中是否回答过这个问题,但我找不到任何答案。

我基本上在一个数据库中有两个表。表 member_privileges 1 保存用户信誉,表 2 保存用户详细信息。它们大致看起来像这样。

mysql> describe member_privileges; 
   +---------------------------+--------------+------+-----+---------+----------------+
        | Field                     | Type         | Null | Key | Default | Extra          |
        +---------------------------+--------------+------+-----+---------+----------------+
        | id                        | int(11)      | NO   | PRI | NULL    | auto_increment |
        | username                  | varchar(255) | YES  |     | NULL    |                |
        | can_comment               | int(11)      | NO   |     | NULL    |                |
        | can_create_articles       | int(11)      | NO   |     | NULL    |                |
        | can_edit_articles         | int(11)      | YES  |     | NULL    |                |
        | can_edit_timeline         | int(11)      | NO   |     | NULL    |                |
        | can_remove_comments       | int(11)      | NO   |     | NULL    |                |
        | can_upload_profile_images | int(11)      | NO   |     | NULL    |                |
        | can_upload_article_images | int(11)      | NO   |     | NULL    |                |
        | can_approve_new_articles  | int(11)      | NO   |     | NULL    |                |
        | can_freez_articles        | int(11)      | NO   |     | NULL    |                |
        +---------------------------+--------------+------+-----+---------+----------------+

这是users表。

mysql> describe users;
+----------------+--------------+------+-----+---------+----------------+
| Field          | Type         | Null | Key | Default | Extra          |
+----------------+--------------+------+-----+---------+----------------+
| id             | int(11)      | NO   | PRI | NULL    | auto_increment |
| username       | varchar(255) | NO   |     | NULL    |                |
| password       | varchar(255) | NO   |     | NULL    |                |
| age            | int(11)      | NO   |     | NULL    |                |
| country        | varchar(255) | NO   |     | NULL    |                |
| email          | varchar(255) | NO   |     | NULL    |                |
| link           | varchar(255) | NO   |     | NULL    |                |
| reg_date       | date         | YES  |     | NULL    |                |
| ip             | varchar(255) | YES  |     | NULL    |                |
| gender         | varchar(10)  | YES  |     | NULL    |                |
| about          | varchar(255) | YES  |     | NULL    |                |
| is_activated   | int(11)      | YES  |     | NULL    |                |
| activation_key | varchar(255) | YES  |     | NULL    |                |
| image_path     | varchar(255) | YES  |     | NULL    |                |
+----------------+--------------+------+-----+---------+----------------+

因此,例如,在一个页面中,我正在尝试检查用户'john'是否具有can_edit_articles权限集。因此,如果在member_privilegesusername"john"将can_edit_articles设置为 1,则该用户可以编辑。

问题是一次检查这些细节。不像我现在这样运行两个查询。

$email = $_SESSION['email']; 
$get_user = "SELECT id, username FROM members WHERE email = $email; 
$can_user_edit = "SELECT can_edit_articles FROM member_privileges WHERE $email = ?;

因此,如您所见,我正在运行两个查询,我想知道是否有任何方法可以在一个 mysql 语句中运行它们。...

使用内部连接并防止 sql 语句进行 sql 注入

如果要选择 id、用户名和can_edit_articles值:

"SELECT m.id, m.username, p.can_edit_articles  
 FROM members m inner join member_privileges p  
 ON m.username=p.username WHERE m.email = '$email'"
$email = $_SESSION['email']; 
$can_user_edit = "SELECT can_edit_articles FROM member_privileges  
                  WHERE username = (SELECT username FROM users WHERE email = '$email')";

您应该在查询中使用 JOIN。 喜欢这个:

SELECT can_edit_articles FROM member_privileges 
P LEFT JOIN  members M ON P.username = M.username WHERE email = '$email'