好吧，标题问题可能听起来令人困惑，是的，我也感到困惑。无论如何，我想要的是这个：假设我有这一行文字，
The quick brown @fox jumps @over the @lazy dog.
是从数据库中动态获取的"单行"，而不是文本数组。假设首字母为"@"的文本是指向页面或其他内容的链接，我希望我可以指定放置锚标签的位置，就我而言，我想在每个文本上放置锚标签以"@"开头。
我尝试过爆炸，但似乎爆炸不是这个问题的答案。有人可以在这里帮助我吗？谢谢。
您不想为此使用explode，而是正则表达式。为了匹配多次出现，preg_match_all是交易。
preg_match_all('/@'w+/', $input, $matches);
# @ is the literal "@" character
# and 'w+ matches consecutive letters
您当然可能希望使用preg_replace将它们转换为链接。或者更好的preg_replace_callback将一些逻辑移动到处理程序函数中。
您可以使用爆炸来处理之前有 @ 的单词... 这实际上取决于您要做什么：
//Store the string in a variable
$textVar = "The quick brown @fox jumps @over the @lazy dog.";
//Use explode to separate words
$words = explode(" ", $textVar);
//Check all the variables in the array, if the first character is a @
//keep it, else, unset it
foreach($words as $key=>$val) {
if(substr($val, 0, 1) != "@") {
unset($words[$key]);
} else {
$words[$key] = "<a href='#'>".$words[$key]."</a>";
}
}
//You can now printout the array and you will get only the words that start with @
foreach($words as $word) {
echo $word."<br>";
}
您还可以保留没有 @ 的字符串，并使用内爆将所有内容放在一起：
//Store the string in a variable
$textVar = "The quick brown @fox jumps @over the @lazy dog.";
//Use explode to separate words
$words = explode(" ", $textVar);
//Check all the variables in the array, if the first character is a @
//keep it, else, unset it
foreach($words as $key=>$val) {
if(substr($val, 0, 1) != "@") {
//Do nothing
} else {
$words[$key] = "<a href='#'>".$words[$key]."</a>";
}
}
//You can now printout the string
$words = implode($words, " ");
echo $words;