在 CakePHP 中创建 2 个表之间的关系，使用模型编写更少的代码 - Creating relationship between 2 tables in CakePHP using models to write less code

Creating relationship between 2 tables in CakePHP using models to write less code

我试着说CkMmUsersKta.user_id=CkSetupUser.id，并在CakePhp中定义2个表之间的关系。我定义了模型并在控制器中的函数中调用了模型，但说未定义的索引

$c['CkSetupUser']['user_name']

蛋糕PHP的注意（8）：未定义的索引：CkSetupUser [APP''Controller''RealsController.php，第 67 行]

我的控制器：

class RealsController extends AppController {
   public $helpers = array('Html', 'Form');
   public $uses =array('CkMmUsersKta','CkSetupUser');
  public function index(){
   $this>loadModel('CkMmUsersKta');$this>loadModel('CkSetupUser');
   ini_set('memory_limit', '2000M');
   $cs=$this->CkMmUsersKta->find("all",array('fields'=>array('CkMmUsersKta.id')));
      foreach($cs as $c):
        echo $c['CkMmUsersKta']['id'].$c['CkSetupUser']['user_name']."<br />";
      endforeach;
   set_time_limit(0); 
   }
}

我的 CkSetupUser 模型：

    public $hasMany = array(
        'CkMmUsersKta' => array(
            'className'     => 'CkMmUsersKta',
            'foreignKey'    => 'user_id',
            'dependent'     => true
        )
    );

我的CkMmUsersKta模型：

    public $belongsTo = array(
        'CkSetupUser' => array(
            'className'    => 'CkSetupUser',
            'foreignKey'    => 'user_id'
        )
    );

问题是您只在以下位置获取 id 字段：

$cs=$this->CkMmUsersKta->find（"all"，array（'fields'=>array（'CkMmUsersKta.id'）））;

您还应该指定名称字段。

$cs=$this->CkMmUsersKta->find（"all"，array（'fields'=>array（'CkMmUsersKta.id'，'CkSetupUser.user_name'）））;