我有一些搜索字段可以查看几个不同的表。
"display_name"表单字段和"最后一个"表单字段显示不同的结果，然后它直接进入phpmyadmin。
如果我在我的 php 脚本中回显出 mysql 查询并将其粘贴到 phpmyadmin 中。它列出了正确的结果。但是在 php/html 页面上，它没有列出相同的内容。
例如。如果某人的全名是内森·斯宾塞，而我将斯宾塞放入"最后一个"表单字段中，则只会显示 1 个结果或 2 个结果。但是，通过将其直接粘贴到phpmyadmin中并运行它，实际上可以找到5个结果。
我一直在为此斗争多年，它让我发疯。
这是页面顶部的 PHP：
<?php
// SEARCH
if(isset($_POST['submit'])) {
// define the list of fields
$fields = array('display_name', 'last', 'suburb', 'state', 'user_type', 'active');
$conditions = array();
// loop through the defined fields
foreach($fields as $field){
// if the field is set and not empty
if(isset($_POST[$field]) && $_POST[$field] != '') {
// create a new condition while escaping the value inputed by the user (SQL Injection)
$conditions[] = "`$field` LIKE '%".mysql_real_escape_string($_POST[$field])."%'";
}
}
// builds the query
$query = "SELECT display_name, first, last, suburb, state, user_type, active FROM nfw_users ";
// if there are conditions defined
if(count($conditions) > 0) {
// append the conditions
$query .= "WHERE " . implode (' AND ', $conditions) .""; // you can change to 'OR', but I suggest to apply the filters cumulative
}
else {
echo "No records found";
}
$result = mysql_query($query);
$score = mysql_fetch_assoc($result);
}
?>
这是 HTML 表单
<form method="post" action="index.php">
<tr>
<td>Name:</td>
<td><input type="text" name="display_name" /></td>
</tr>
<tr>
<td>Street:</td>
<td><input type="text" name="last" /></td>
</tr>
<tr>
<td>Suburb:</td>
<td><input type="text" name="suburb" /></td>
</tr>
<tr>
<td>State:</td>
<td>
<select name="state">
<option>
<option value="qld">QLD</option>
<option value="sa">SA</option>
<option value="nt">NT</option>
<option value="wa">WA</option>
<option value="vic">VIC</option>
<option value="tas">TAS</option>
<option value="act">ACT</option>
</select>
</td>
</tr>
<tr>
<td>Type:</td>
<td>
<select name="user_type">
<option>
<option value="franchise">Franchisee</option>
<option value="regional">Regional</option>
<option value="state">State</option>
<option value="national">National</option>
<option value="office">Headoffice Staff</option>
</select>
</td>
</tr>
<tr>
<td>Active:</td>
<td>
<select name="active">
<option></option>
<option value="1">Active</option>
<option value="0">Not Active</option>
</select>
</td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="submit" value="Search" /></td>
</tr>
</form>
<form method="post" action="index.php">
<tr>
<td>Name:</td>
<td><input type="text" name="display_name" /></td>
</tr>
<tr>
<td>Street:</td>
<td><input type="text" name="last" /></td>
</tr>
<tr>
<td>Suburb:</td>
<td><input type="text" name="suburb" /></td>
</tr>
<tr>
<td>State:</td>
<td>
<select name="state">
<option>
<option value="qld">QLD</option>
<option value="sa">SA</option>
<option value="nt">NT</option>
<option value="wa">WA</option>
<option value="vic">VIC</option>
<option value="tas">TAS</option>
<option value="act">ACT</option>
</select>
</td>
</tr>
<tr>
<td>Type:</td>
<td>
<select name="user_type">
<option>
<option value="franchise">Franchisee</option>
<option value="regional">Regional</option>
<option value="state">State</option>
<option value="national">National</option>
<option value="office">Headoffice Staff</option>
</select>
</td>
</tr>
<tr>
<td>Active:</td>
<td>
<select name="active">
<option></option>
<option value="1">Active</option>
<option value="0">Not Active</option>
</select>
</td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="submit" value="Search" /></td>
</tr>
</form>
这是打印到表格中的结果
<?php if(isset($score)){
while($score=mysql_fetch_assoc($result)){
$display_name = $score['display_name'];
$lastname = $score['last'];
$state = $score['state'];
$active = $score['active'];
if ($active=='1') {
$activeother = "<i class='fa fa-check' style='color:green;'></i>";
}
else {
$activeother = "<i class='fa fa-times' style='color:red;'></i>";
}
?>
<?php
$content = "<tr><td>" . $score['display_name'] . "</td><td>" . $score['first'] . "</td><td>" . $score['last'] . " </td><td>" . $score['email'] . " </td><td> " . $score['mobile'] . " </td><td> " . $score['landline'] . "</td><td>$activeother</td><td> " . $score['user_type'] . "</td><td> " . date('d-m-Y', strtotime($score['date_join'])) . "</td><td class='invoicing-columns'><a class='btn btn-yellow' href='view-invoices.php?id=" . $score['id_num'] . "'><i class='fa fa-eye'></i></a></td><td class='invoicing-columns'><a class='btn btn-red' href='del-customers.php?id=" . $score['id_num'] . "' onclick='return check();' class='delete'><i class='fa fa-minus-circle'></i></a></td></tr>";
echo $content;
}}
?>
如果我
的代码正确，可能会出现问题：在这里，您实际上获取了第一行。
$result = mysql_query($query);
$score = mysql_fetch_assoc($result);
然后似乎你只是跳过它并循环：
if(isset($score)){
while($score=mysql_fetch_assoc($result)){
你真正想做的是：
$result = mysql_query($query);
if (!$result) {
//TODO: Query error handling
}
// This is how you check for results count
if (mysql_num_rows($result) == 0) {
while ($score = mysql_fetch_assoc($result)) {
//Here you go with result
}
}
您也可以查看此手册链接作为参考。
接下来要检查，从查询中获取确切的字符串，然后从phpMyAdmin尝试。在执行查询时，请确保使用与代码相同的用户。
还有一件事，您正在使用的扩展已被长期弃用，您应该考虑切换到MySQLi或PDO_MySQL