DELETE statement php MySQL

本文关键字：MySQL php statement DELETE | 更新日期: 2023-09-27

我的代码需要一些帮助，当我点击提交代码时，它总是说"用户成功踢出"。但是，查询未成功执行，用户仍在数据库中。

edit：修复了mysql/msqli问题。查询现在回答"出现问题"，而不是"用户已成功踢出"。但是我不会从mysql_error报告中得到任何错误。我能做什么？

include 'connect.php';
if(empty($_POST['user_id'])) 
    {
            echo '<form method="post" action="">
                  User_id: <input type="text" name="user_id" />
                 <input type="submit" value="Kick user" />
                 </form>';
    }
    else 
    {
        $sql = "DELETE FROM users
                WHERE 
                user_id = '" .mysqli_real_escape_string($_POST['user_id']) . "'
                ";
        $result = mysqli_query($con, $sql);
        if($result)
        {
            //something went wrong, display the error
            echo 'Something went wrong!.';
            echo mysqli_error(); //debugging purposes, uncomment when needed
        }
        else
        {
            echo 'User successfully kicked!';
        }
    }

我的connect.php如下：

<?php
$con=mysqli_connect ("localhost","root","","dps");
if (mysqli_connect_errno()) {
echo "failed to connect mysql: ". mysqli_connect_error();
}
?>

您正在if部分设置$sql var，并尝试在else部分访问它。这不起作用。此外，您正在混合糟糕的库（mysql与mysqli不同，使用mysqli是因为mysql已被弃用，并将从php中删除）

include 'connect.php';
if(empty($_POST['user_id'])) 
{
        echo '<form method="post" action="">
              User_id: <input type="text" name="user_id" />
             <input type="submit" value="Kick user" />
             </form>';
}
else 
{
    $sql = "DELETE FROM users
            WHERE 
            user_id = '" .mysqli_real_escape_string($con, $_POST['user_id']) . "'
            ";
    $result = mysqli_query($con, $sql);
    if(!$result)
    {
        //something went wrong, display the error
        echo 'Something went wrong!: ';
        echo mysqli_error($con) //debugging purposes, uncomment when needed
    }
    else
    {
        echo 'User succesfully kicked!';
        mysqli_free_result($result);
    }
}

您可能需要更改connect.php才能使用mysqli

编辑：有些错误现在应该修复

添加：

$result = mysqli_query($con, $sql);

之后：

$sql = "DELETE FROM 
                    users
                WHERE 
                    user_id = '" . mysql_real_escape_string($_POST['user_id']) . "'
                ";