我有一个普通的php联系人表单示例，我对其进行了修改以满足我的需求。然后我想使用ajax发布到我的php邮件脚本中。出于某种原因，我仍然在我的url中看到这样的post值：
http://www.example.com?name=bruno&email=bruno%40gmail.com&subject=ajax+test+ff&message=test
我也没能从php中得到正确的响应，判断发送是否成功。如果成功，我想显示一条消息。
然而，电子邮件发送。
这是我的代码：
HTML
<form>
<input type="text" class="form-control" id="name" name="name" placeholder="Name">
<input type="email" id="email" name="email" class="form-control" placeholder="Email">
<input type="text" class="form-control" id="subject" name="subject" placeholder="Subject">
<textarea class="form-control" id="message" name="message" placeholder="Message" rows="4"></textarea>
<button id="submit" class="form-control text-uppercase">Send</button>
</form>
jQuery
$( document ).ready(function() {
$("#submit").click(function(){
var data = {
name:$("#name").val(),
email:$("#email").val(),
subject:$("#subject").val(),
message:$("#message").val(),
}
$.ajax({
type: "POST",
url: "sendmail.php",
data: data,
dataType: 'json',
cache: false,
})
.success(function(response) {
if(!response.errors && response.result=="success") {
alert("success")
} else
if(!response.errors && response.result=="oops") {
alert("oops somethign went wrong");
}
});
});
});
PHP
<?php
$inputvalues = $_POST;
$errors = false;
$result = false;
$email_to = "bruno@example.com";
$email_from = "info@example.com";
$name = $inputvalues["name"];
$email = $inputvalues["email"];
$message = $inputvalues["message"];
$email_subject = $inputvalues["subject"];
$headers = "From: " . $email_from . "'n";
$headers .= "Reply-To: " . $email . "'n";
$message = "Name: ". $name . "'r'nMessage: " . $message;
ini_set("sendmail_from", $email_from);
$sent = mail($email_to, $email_subject, $message, $headers, "-f" .$email);
if ($sent) {
$returnResult = "success";
}
else {
$returnResult = "oops";
}
echo json_encode(['result' => $returnResult, 'errors' => $errors]);
?>
您需要防止在侦听器中提交表单，即
$( document ).ready(function() {
$("#submit").click(function(event){
event.preventDefault();
var data = {
// etc.