如果最后一个值等于新的值,如何跳过插入数组?下面的代码产生了12345555555667,但我只想要1234567,这意味着没有一个值是重复的。
$NumArray = array('1','2','3','4','5','5','5','5','5','5','5','6','6','7');
$SecondArray = array();
foreach($NumArray as $num){
$SecondArray[] = array(
'alpa'=>$num
);
}
echo json_encode($SecondArray);
$NumArray = array();
$numArray = array('1','2','3','4','5','5','5','5','5','5','5','6','6','7');
foreach($NumArray as $num){
if ($previousNumber != $num) {
echo $num;
$previousNumber = $num;
}
}
使用array_unique()
$NumArray = array();
$NumArray =array('1','2','3','4','5','5','5','5','5','5','5','6','6','7');
$NumArray = array_unique($NumArray) ;
foreach($NumArray as $num){
echo $num;
}
简单:
$NumArray = array('1','2','3','4','5','5','5','5','5','5','5','6','6','7');
$NumArray = array_unique($NumArray);
偶数:
$NumArray = array_unique(array('1','2','3','4','5','5','5','5','5','5','5','6','6','7'));
这将确保在首次填充数组时只添加唯一元素。编辑:
if (!in_array($someNewValue, $NumArray))
{
$NumArray[] = $someNewValue;
}
使用array_unique()
$numArray = array('1','2','3','4','5','5','5','5','5','5','5','6','6','7');
echo json_encode(array_unique($numArray));
试试这个:
for ($i = 0; $i <count($NumArray); $i++)
{
for ($k = $i+1; $k <count($NumArray); $k++)
{
if ($k != $i && $NumArray[$i] == $NumArray[$k])
{
$NumArray[$k]="";
}
}
}
现在数组"NumArray"只包含原子值。
您可以使用array_unique
获取数组的唯一值,然后对其进行迭代。
$NumArray = array('1','2','3','4','5','5','5','5','5','5','5','6','6','7');
$unique_arr = array_unique($NumArray) ;
foreach($UniqueArray as $num){
echo $num;
}
if (end($NumArray) != $someNewValue){
$NumArray = $someNewValue;
}